Answer:
1 A true
B False
C not sure about it False
D False
Answer:
a. 300 Kg of fertilizer
b. 225 Kg of fertilizer
c. 400 Kg of fertilizer
d. 600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.
Therefore a 1 Kg bag contains;
40/100 * 1 Kg = 0.4 Kg of Nitrogen;
15/100 * 1 Kg = 0.15 Kg of phosphorus;
10/100 * 1 Kg = 0.1 Kg of potassium
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at a rate of 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
Answer:
Kp = 41.53
Kc = 1.01
Explanation:
To calculate the equilibrium constant in terms of pressure, what we simply do is to use the equilibrium pressure raised to the power of the number of moles. What we are saying in essence is this:
Kp = [NOCl]^2/[NO]^2[Cl]
Kp= [0.25]^2/[0.174][0.093]^2 = 41.53
Kp = Kc (RT)^Dn
Hence, Kc = Kp/[RT]^(delta n )^-1
n = sum of the number of moles of products minus the sum of the number of moles of reactants= 2-3 = -1 in this case
Kc = 41.53/(0.0821 * 500)^1
Kc = 1.01
Answer:
d = 14.9 g/mL
Explanation:
Given data:
Mass of metal = 22.4 g
Volume of eater = 3.2 mL
Volume of water + metal = 4.7 mL
Density of metal = ?
Solution:
Volume of metal:
Volume of metal = volume of water+ metal - volume of water
Volume of metal = 4.7 mL - 3.2 mL
Volume of metal = 1.5 mL
Density of metal:
d = m/v
d = density
m = mass
v = volume
d = 22.4 g/ 1.5 mL
d = 14.9 g/mL
Answer:
I think its False
Explanation:
ozone layer surroundes the atmosphere and traps the heat
