5000 units of antigens are present in 0.5 mL of the mumps virus vaccine.
Volume of the vaccine after dilution with water = 2 mL
0.5 mL has 5000 units antigen. So when 0.5 mL was diluted to 2 mL, the final vaccine after dilution would contain 5000 units of antigen.
Units of antigen present in 1 mL vaccine sample
=
Therefore, 2500 units of the antigen will be present in each milliliter, if 0.5 mL of the vaccine is diluted to 2 mL with water for injection.
Answer:
Partial Pressure Of Water Vapor Is 18.65mmHg At 21C0. ... How many liters of H2 gas , collected over water at an atmospheric pressure of 752 mmHg and a temperture of 21 Co, can made from 3.566 g of Zn
Explanation:
Answer:
Number of moles = 10.6 mol
Explanation:
Given data:
Molar mass of H = 1.008 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)
Number of moles of citric acid = ?
Solution:
Formula:
Number of moles = mass/molar mass
Now we will calculate the molar mass of citric acid:
C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)
C₆H₈O₇ = 72.06 + 8.064+112
C₆H₈O₇ = 192.124g/mol
Number of moles = 2030 g/ 192.124g/mol
Number of moles = 10.6 mol