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fomenos
2 years ago
8

A compound has the empirical formula CH2O. If the compound’s molecular mass is 180 g/mol, determine the molecular formula of the

compound. Be sure to show your work.
Chemistry
1 answer:
Umnica [9.8K]2 years ago
3 0
The molecular formula will be a multiple of the empirical CH2O. One unit of CH2O has a mass of 12+2*1+16 = 30 g. This means that if our compound has a molecular mass of 180 g/mol, we can divide 180 / 30 = 6 units, and our compound has 6 units of CH2O. This means that its molecular formula is C6H12O6.
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Which balance is a centigram balance? <br> A <br> Or <br> B
MaRussiya [10]
I think it is B because you didn’t type the options
5 0
3 years ago
Draw the structure of 2 methyl,but-3-ene
Maslowich

Answer:

Please find the structure attached as an image

Explanation:

Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.

- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.

- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).

N.B: In the structure attached below, the counting is from the left to right (→).

5 0
2 years ago
The overall cell reaction occurring in an alkaline battery isZn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s) (e) In practice, vol
zubka84 [21]

b) Mass of MnO₂ = 5.981 g

    Mass of H₂O = 1.2384 g

c) Total Mass of Reactant consumed = 11.708 g

b) Given Reaction

            Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

  Mass of Zn = 4.50 g

  Moles of Zn = 0.0688 moles

   Now,

    Moles of Zn = moles of MnO₂ = moles of H₂O = moles of ZnO = moles of                   Mn(OH)₂

Hence ,

Moles of MnO₂ = 0.0688 moles

Mass of MnO₂ = 0.0688 × 86.9368 g

                        = 5.981 g

Similarly,

    Moles of H₂O = 0.0688 moles

     Mass of H₂O = 0.0688 × 18 g

                           = 1.2384 g

c) now ,

    Moles of  ZnO = 0.0688 moles

     Mass of  ZnO  = 0.06880× 81.3794 g

                              = 5.598 g

 Moles of  Mn(OH)₂ = 0.0688 moles

  Mass of  Mn(OH)₂ =0.0688 × 88.952 g

                                  = 6.11 g

Total mass of Product = 11.708 g

Total Mass of Reactant = 11.715 g

Hence,

    Total mass of reactant consumed = 11.708 g

c)  As total mass of reactant is more than that of mass of reactant consumed , Hence G is more than that of mass of reactant consumed .

G = - nFEcell

 

and no. of moles of reactant  is greater than that of number of moles of reactant consumed .

       Hence voltaic cell of given Capacity are heavier than that of mass of reactant consumed .

 Thus from above conclusion we can say that , Mass of the reactant consumed is 11.708 g.

Learn more about Galvanic Cell here : brainly.com/question/19340007

#SPJ4

3 0
1 year ago
Name the acids: HBrO
solong [7]

Answer:

Hypobromous acid

Explanation:

6 0
3 years ago
A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
lapo4ka [179]

Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

Q = mc∆T

Where;

Q = amount of heat

m = mass of substance

c = specific heat of substance

∆T = change in temperature

Hence;

-{mc∆T} of metal = {mc∆T} of water

From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.

For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

The specific heat capacity of the metal is 0.1988 J/g°C

6 0
2 years ago
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