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ad-work [718]
3 years ago
11

Dense water near the poles sinks, creating a current towards the equator. What would you expect to happen to this current if tem

peratures at the poles increased?
A. The current would move to the surface
B. Nothing would happen to the current
C. The current would decrease in speed
D. The current would increase in speed
Physics
1 answer:
Rudik [331]3 years ago
3 0
It's not c or d :/!!!!!
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3 years ago
. Write the following in the scientific notation of 0.0000002400m ​
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Explanation:

<h2><u>Steps </u><u>:</u></h2>
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7 0
2 years ago
An 80-cm uniform 10-kg bar is resting on two scales, one at either end. A smaller 4-kg mass (m) is placed at a distance of d = 2
Varvara68 [4.7K]

Answer

given,

length of bar = 80 cm

mass of the bar = 10 kg

smaller mass = 4 kg

distance = 20 cm

s_1 + s_2 = 10 + 4

s_1 + s_2 = 14\ kg

taking moment about B

s_1 \times 0.8 - 10 \times 0.4 - 4 \times 0.6 = 0

s_1 \times 0.8 = 6.4

s_1 = 8\ N

s_2 = 14 - s_1

s_2 = 14 - 8

s_2 = 6 N

difference between two scale = 8 - 6

                                                  = 2 N

7 0
3 years ago
PLS HELP ME OUT!!
MaRussiya [10]
In order to solve this problem, we must first find out the value of each line on the number line. However, we can make this problem more simple by ignoring every interval except for the ones between 0 and 6. There are three total intervals in between 0 and 6 (including 6 and excluding 0). Therefore, we can do 6/2, and get an interval value of 2. This means that each line adds a value of 2. Since the car is only one line past zero, we only have to add one value of 2. Since 0 + 2 = 2, our final answer is C. 2.

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4 0
3 years ago
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A 200.0 kg piano is elevated by a crane to a height of 10.0 meters above a sidewalk. If the rope holding the piano breaks, what
Nitella [24]
All that business about the crane and the rope and the falling
is only there to confuse us.

The piano ended up 5 meters above the ground.

           Potential energy = (mass) (gravity) (height)

                                   = (200 kg) (9.81 m/s²) (5 m)

                                   = (200 · 9.81 · 5)  (kg-m²/s²)

                                   =   9,810 joules   . 
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3 years ago
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