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riadik2000 [5.3K]
3 years ago
15

What is (9.8) / (6.75x10-6)

Physics
1 answer:
ratelena [41]3 years ago
3 0

sorry, it's B, not a made a mistake in the approximation

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A student pushes a 0.2 kg box against a spring causing the spring to compress 0.15 m. When the spring is released, it will launc
german

Answer:

The maximum height the box will reach is 1.72 m

Explanation:

F = k·x

Where

F = Force of the spring

k = The spring constant = 300 N/m

x  = Spring compression or stretch = 0.15 m

Therefore the force, F of the spring = 300 N/m×0.15 m = 45 N

Mass of box = 0.2 kg

Work, W, done by the spring = \frac{1}{2} kx^2 and the kinetic energy gained by the box is given by KE = \frac{1}{2} mv^2

Since work done by the spring = kinetic energy gained by the box we have

\frac{1}{2} mv^2 =  \frac{1}{2} kx^2  therefore we have v = \sqrt{\frac{kx^2}{m} } = x\sqrt{\frac{k}{m} } = 0.15\sqrt{\frac{300}{0.2} } = 5.81 m/s

Therefore the maximum height is given by

v² = 2·g·h or h = \frac{v^2}{2g} = \frac{5.81^{2} }{2*9.81} = 1.72 m

6 0
3 years ago
Need the answer for question 5 :)
kykrilka [37]

Answer:

1 B. Convert v from km/min to m/s ( show work and units

3 0
2 years ago
The volume of a fixed mass of gas is directly proportional to its
Leni [432]

Answer: Charles's law

Explanation:

Charles's law is one of the gas laws, and it explains the effect of temperature changes on the volume of a given mass of gas at a constant pressure. Usually, the volume of a gas decreases as the temperature decreases and increases as the temperature also increases.

Mathematically, Charles's law can be expressed as:

V ∝ T

V = kT or (V/T) = k

where v is volume, T is temperature in Kelvin, and a k is a constant.

7 0
3 years ago
A textbook of mass 2.02 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
Anika [276]

Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

7 0
3 years ago
1. A densidade do nitrogênio nas condições normais de temperatura e pressão é igual a 1,24507 kg/m³. Qual a massa de 200 cm³ de
Levart [38]

Answer:

5.49×10⁻⁴ lbm

Explanation:

Convert volume to m³.

V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³

Find mass in kg.

m = ρV

m = (1.24507 kg/m³) (0.0002 m³)

m = 0.000249 kg

Convert mass to lbm.

m = (0.000249 kg) (2.205 lbm/kg)

m = 0.000549 lbm

m = 5.49×10⁻⁴ lbm

3 0
3 years ago
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