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3 years ago

Which BEST describes the difference between speed and velocity?

Physics

2 answers:

kirill [66]3 years ago

6 0

Answer : The correct option is, (D) Velocity includes rate of change and direction.

Explanation :

Speed : Speed is defined as the distance traveled by an object with respect to the time taken. It is a scalar quantity that means it tell us about the magnitude of an object not direction.

Velocity : Velocity is defined as the rate of change of position of an object with respect to the time. It is a vector quantity that means it tell us about the magnitude and direction of an object.

The only difference between the speed and the velocity is that the velocity tell us about magnitude and direction but speed tell us about magnitude only.

Hence, the correct option is, (D) Velocity includes rate of change and direction.

Sliva [168]3 years ago

3 0

The magnitude of a speed completely defines it whereas you also need to state a direction to specify a velocity.

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3 years ago

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3 years ago

Will mark as brainlist for only correct answer

Crank

Answer:

low, low

Explanation:

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3 years ago

A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider

shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

$d=v_x t$

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

$v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s$

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

$y(t) = h + v_y t - \frac{1}{2}gt^2$

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

$0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s$

So now we can find the magnitude of the initial velocity:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s$

4 0

3 years ago

The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s

notka56 [123]

Answer:

P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

I = P / A

Since sound is distributed in all directions spherical shape, the area of a sphere is

A = 4π r²

let's clear the power and replace

P = I A

P = I (4π r²)

let's calculate

P = 5.00 (4π 2²)

P = 251, 3 W

6 0

3 years ago