4 years ago

Calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30ms

1 answer:

6 0

S= ?
U= 0 $ms^{-1}$
V= 30 $ms^{-1}$
A= 9.8 $ms^{-2}$
T=

$V^2 = U^2 + 2AS$
$900 = 19.6S$
$\frac{900}{19.6} = S$
S = 45.92 $m$

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