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Dmitrij [34]
4 years ago
5

Calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30ms

Physics
1 answer:
nexus9112 [7]4 years ago
6 0
S= ?
U= 0 ms^{-1}
V= 30 ms^{-1}
A= 9.8 ms^{-2}
T= 

V^2 = U^2 + 2AS
900 = 19.6S
\frac{900}{19.6} = S
S = 45.92 m
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