Answer:
Average :
UCL = 4.15
LCL = 2.65
Range :
UCL = 2.75
LCL = 0
Explanation:
Given :
Sample size, n = 5
Average, X = 3.4
Range, R = 1.3
A2 for n = 5 ; equals 0.577 ( X chart table) 
For the average :
Upper Control Limit (UCL) :
X + A2*R
3.4 + 0.577(1.3) = 4.1501
Lower Control Limit (LCL) :
X - A2*R
3.4 - 0.577(1.3) = 2.6499
FOR the range :
Upper Control Limit (UCL) :
UCL = D4*R
D4 for n = 5 ; equals = 2.114
UCL = 2.114*1.3 = 2.7482
Lower Control Limit (LCL) :
LCL = D3*R
D3 for n = 5 ; equals = 0
LCL = 0 * 1.3 = 0
 
        
             
        
        
        
Answer:
29274.93096 m/s




Explanation:
 = Distance at perihelion =
 = Distance at perihelion = 
 = Distance at aphelion =
 = Distance at aphelion = 
 = Velocity at perihelion =
 = Velocity at perihelion = 
 = Velocity at aphelion
 = Velocity at aphelion
m = Mass of the Earth =  5.98 × 10²⁴ kg
M = Mass of Sun = 
Here, the angular momentum is conserved

Earth's orbital speed at aphelion is 29274.93096 m/s
Kinetic energy is given by

Kinetic energy at perihelion is 
Potential energy is given by

Potential energy at perihelion is 

Kinetic energy at aphelion is 
Potential energy is given by

Potential energy at aphelion is 
 
        
             
        
        
        
If you put it into English in the comments I would be more then happy to help you! Thank you!