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stiks02 [169]
3 years ago
7

Does corrosion occur when iron nail is in salt water

Chemistry
1 answer:
yarga [219]3 years ago
5 0

Answer:

Yes

Explanation:

: The corrosion of iron indicates a chemical change in the metal. ... Where salt is present, electrochemical corrosion occurs, and the protective oxide film does not form, thus the corrosion (buildup of rust) continues unchecked. Your iron nail will indeed rust more quickly and severely in salt water.

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Which isomer of 1-bromo-2-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?Draw the structure of t
ivolga24 [154]

Answer:

See explanation and image attached

Explanation:

The reaction of 1-bromo-2-tert-butylcyclohexane with  potassium tert-butoxide is an elimination reaction that occurs by E2 mechanism.

The E2 reaction proceeds faster when the hydrogens are in an antiperiplanar position at an angle of 180 degrees.

This is only attainable in the trans isomer of 1-bromo-2-tert-butylcyclohexane. Hence trans 1-bromo-2-tert-butylcyclohexane reacts faster with potassium tert-butoxide

8 0
3 years ago
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
Dorothy left a frozen juice pop out on the counter. When she returned, the juice pop had melted into a liquid. Which of the foll
Brums [2.3K]

Answer:

B) The molecules were closer together when the juice pop was frozen.

8 0
3 years ago
Which of the following equations are correctly balanced?
AlladinOne [14]

i think it's I

I was confused by IV then search on gg and it said ZnSO4 should be Zn2SO4 instead but still im not sure Zn2SO4 is real

3 0
3 years ago
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