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DedPeter [7]
4 years ago
14

I need help with 13-31 just got off break today please

Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
3 0
To turn a percent to a decimal, start at the decimal, and move it 2 spaces to the left
13. 100.8% = 1.008
14. 5.17% = 0.0517

I cant see 14 or 15.....or all of 17
17. I cant see all of it, but the correct way would be :
      1.475% = 0.01475

to turn a decimal to a percent, move the decimal 2 spaces to the right...I cant see all of these but I will do the ones that I can see..
18. 0.66 = 66%
19. 0.32 = 32%
22. 0.01 = 1%
23. 0.04 = 4%
26. 0.5 = 50%
27. 1.2 = 120%
30. 0.003 = 0.3%
31. 0.025 = 2.5%




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Ad libitum [116K]
Pom would be in 6th place

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4 years ago
Question#1 Please simplify..
riadik2000 [5.3K]
Hey there,
6x + 5 (x-2)
6x + 5x - 10
11x - 10

3x - 5 - x + 9 
3x - x - 5 + 9
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3 (-1) + 5 - 8(-1) + 1
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5 0
3 years ago
Represent 42 divided by 6 = 7 using subtraction
GuDViN [60]

Answer:

42 - 6 - 6 - 6 - 6 - 6 - 6 - 6 = 0

or

42 - 7 - 7 - 7 - 7 - 7 - 7 = 0

5 0
3 years ago
A study was conducted to investigate the effectiveness of hypnotism in reducing pain. An SRS of 8 subjects was randomly selected
chubhunter [2.5K]

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!

5 0
3 years ago
Find the measure of one interior angle of a regular 21-gon.
ExtremeBDS [4]
C step-by-step the coordinate of that is pretty simple to say but hard at the same time
5 0
2 years ago
Read 2 more answers
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