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o-na [289]
3 years ago
8

What is the never repeat rule

Engineering
1 answer:
Soloha48 [4]3 years ago
4 0
Don't repeat yourself (DRY, or sometimes do not repeat yourself) is a principle of software development aimed at reducing repetition of software patterns,[1] replacing it with abstractions or using data normalization to avoid redundancy.
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Water is flowing at a rate of 0.15 ft3/s in a 6 inch diameter pipe. The water then goes through a sudden contraction to a 2 inch
Georgia [21]

Answer:

Head loss=0.00366 ft

Explanation:

Given :Water flow rate Q=0.15 \frac{ft^{3}}{sec}

         D_{1}= 6 inch=0.5 ft

        D_{2}=2 inch=0.1667 ft

As we know that Q=AV

A_{1}\times V_{1}=A_{2}\times V_{2}

So V_{2}=\frac{Q}{A_2}

     V_{2}=\dfrac{.015}{\frac{3.14}{4}\times 0.1667^{2}}

     V_{2=0.687 ft/sec

We know that Head loss due to sudden contraction

           h_{l}=K\frac{V_{2}^2}{2g}

If nothing is given then take K=0.5

So head lossh_{l}=(0.5)\frac{{0.687}^2}{2\times 32.18}

                                    =0.00366 ft

So head loss=0.00366 ft

4 0
3 years ago
Conclude from the scenario below which type of documentation Holly should use, and explain why this would be the best choice. Ho
NARA [144]

Answer:

Okay

Explanation:

7 0
3 years ago
Can i have answer of this question please?
cestrela7 [59]

uh its a tough one mate

3 0
3 years ago
An equation used to evaluate vacuum filtration is Q = ΔpA2 α(VRw + ARf) , Where Q ≐ L3/T is the filtrate volume flow rate, Δp ≐
larisa86 [58]

Answer:

Explanation:

The explanations and answers are shown in the following attachments

6 0
3 years ago
A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg wa
BigorU [14]

Answer:

HB = 3.22

Explanation:

The formula to calculate the Brinell Hardness is given as follows:

HB = \frac{2P}{\pi D\sqrt{D^{2}- d^{2} } }

where,

HB = Brinell Hardness = ?

P = Applied Load in kg = 500 kg

D = Diameter of Indenter in mm = 10 mm

d = Diameter of the indentation in mm = 1.55 mm

Therefore, using these values, we get:

HB = \frac{(2)(500)}{\pi (10)\sqrt{10^{2}- 1.55^{2} } }

<u>HB = 3.22 </u>

4 0
3 years ago
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