Answer:
6.6 kilo volts = 6.6 k volts
Explanation:
A prefix is a word, number or a letter that is added before another word. In physics we have different prefixes for the exponential powers of 10, that are placed before units in place of those powers. Some examples are:
deci (d) ------ 10⁻¹
centi (c) ------ 10⁻²
milli (m) ------ 10⁻³
kilo (k) ------ 10³
mega (M) ----- 10⁶
giga (G) ------ 10⁹
We have:
6600 volts
converting to exponential form:
=> 6.6 x 10³ volts
Thus, we know that the prefix of kilo (k) is used for 10³.
Hence,
=> <u>6.6 kilo volts = 6.6 k volts</u>
Explanation:
Note: Refer the diagram below
Obtaining data from property tables
State 1:
State 2:
State 3:
State 4:
Throttling process 
(a)
Magnitude of compressor power input
(b)
Refrigerator capacity
(c)
Cop:
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
The attached file gave a detailed solution of the problem.
Answer:
Yes
Explanation:
As we know that octane number resist the engine from knocking.If knocking can prevent that automatically the performance of engine will increases.If octane number is 100 then it means that knocking tendency in the engine is zero.So higher the octane number better will the performance of the engine.
Generally octane number is 87 but for premier gasoline is 92 or 93.
So we can say that if octane number is 93 then car will give better performance
Answer:
The diameter is 50mm
Explanation:
The answer is in two stages. At first the torque (or twisting moment) acting on the shaft and needed to transmit the power needs to be calculated. Then the diameter of the shaft can be obtained using another equation that involves the torque obtained above.
T=(P×60)/(2×pi×N)
T is the Torque
P is the the power to be transmitted by the shaft; 40kW or 40×10³W
pi=3.142
N is the speed of the shaft; 250rpm
T=(40×10³×60)/(2×3.142×250)
T=1527.689Nm
Diameter of a shaft can be obtained from the formula
T=(pi × SS ×d³)/16
Where
SS is the allowable shear stress; 70MPa or 70×10⁶Pa
d is the diameter of the shaft
Making d the subject of the formula
d= cubroot[(T×16)/(pi×SS)]
d=cubroot[(1527.689×16)/(3.142×70×10⁶)]
d=0.04808m or 48.1mm approx 50mm
