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3 years ago

Describe the relationship between atomic structure and Youngs' modulus?

Engineering

1 answer:

Stolb23 [73]3 years ago

5 0

Answer:

The relationship between atomic structure and Youngs modulus could be defined as the stiffness of a material.

Explanation:

Young modulus is a constant that shows how a material can be deformed under a stress applied on certain material and also shows its stiffness, this deformation will change or not its atomic structure depending on the capability of material to recover from the stress applied. The stiffness of a material is directly proportional to Young's modulus, as well as its atomic structure, if a material has high stiffness, it won't bend so easily and it won't change its atomic structure easily.

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Ok there........................................................................

Juliette [100K]

Answer:

ok THERE

Explanation:

4 0

2 years ago

An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. A

irina [24]

An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile at a constant acceleration of 1.96 m/s2 . The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s2

Find the total time required for the police car to over take the automobile.

Answer:

15.02 sec

Explanation:

The total time required for the police car to overtake the automobile is related to the distance covered by both cars which is equal from instant point of abreast.

So; we can say :

$D_{pursuit} =D_{police}$

By using the second equation of motion to find the distance S;

$S= ut + \dfrac{1}{2}at^2$

$D_{pursuit} = (15.65 *12 )+(15.65 (t)+ (\dfrac{1}{2}*(-3.05)t^2)$

$D_{pursuit} = (187.8)+(15.65 \ t)-0.5*(3.05)t^2)$

$D_{pursuit} = (187.8+15.65 \ t-1.525 t^2)$

$D_{police} = ut _P + \dfrac{1}{2}at_p^2$

where ;

u = 0

$D_{police} = \dfrac{1}{2}at_p^2$

$D_{police} = \dfrac{1}{2}*(1.96)*(t+12)^2$

$D_{police} = 0.98*(t+12)^2$

$D_{police} = 0.98*(t^2 + 144 + 24t)$

$D_{police} = 0.98t^2 + 141.12 + 23.52t$

Recall that:

$D_{pursuit} =D_{police}$

$(187.8+15.65 \ t-1.525 t^2)= 0.98t^2 + 141.12 + 23.52t$

$(187.8 - 141.12) + (15.65 \ t - 23.52t) -( 1.525 t^2 - 0.98t^2) = 0$

= 46.68 - 7.85 t -2.505 t² = 0

Solving by using quadratic equation;

t = -6.16 OR t = 3.02

Since we can only take consideration of the value with a positive integer only; then t = 3.02 secs

From the question; The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit;

Therefore ; the total time required for the police car to over take the automobile = 12 s + 3.02 s

Total time required for the police car to over take the automobile = 15.02 sec

8 0

2 years ago

A heating system must maintain the interior of a building at 20°C during a period when the outside air temperature is 5°C and th

Anettt [7]

Answer:

a. W = 51,194.54 kJ

b. W = 102,390 kJ

c. W = 153,585 kJ

Explanation:

$(COP)_{HP} =\frac{Desired-effectx}{Work-done}= \frac{Q_{1} }{W} \\\\(COP)_{HP} =(COP)_{Ideal}\\\\\frac{Q1}{W} =\frac{T_{1} }{T_{1} -T_{2} }$

$W=Q_{1} \frac{T_{1}-T_{2} }{T_{1} }$

a. the ground at 15°C.

$T_{1}$ =20°C = 273 K + 20 = 293 K

$T_{2}$ =15°C = 273 K + 15 = 288 K

$Q_{1}=3x10^{6} kJ$

$W=3x10^{6} kJ \frac{293 K-288 K}{293 K}=3x10^{6} kJ \frac{5 K}{293 K}=3x10^{6} kJ x 0.017065}$

$W = 0.051195x10^{6} kJ$

W = 51,194.54 kJ

b. a pond at 10°C.

$T_{2}$ =10°C = 273 K + 10 = 283 K

$W=3x10^{6} kJ \frac{293 K-283 K}{293 K}=3x10^{6} kJ \frac{10 K}{293 K}=3x10^{6} kJ x 0.034130}$

$W = 0.102390x10^{6} kJ$

W = 102,390 kJ

c. the outside air at 5°C.

$T_{2}$ =5°C = 273 K + 5 = 278 K

$W=3x10^{6} kJ \frac{293 K-278 K}{293 K}=3x10^{6} kJ \frac{15 K}{293 K}=3x10^{6} kJ x 0.051195}$

$W = 0.153585x10^{6} kJ$

W = 153,585 kJ

Hope this helps!

3 0

2 years ago

Facts about cellphones

alina1380 [7]

Answer:

Your mobile phone has more computing power than the computers used for the Apollo 11 moon landing.

Mobile phones have to “work harder” to get a signal if you are in a moving vehicle.

The first mobile phone was made in 1973.

The first mobile phones that went on sale in 1983 cost nearly $4,000 each.

In 2012 Apple sold 340,000 phones per day.

4 out of 10 Brits admit to snooping on their partners phone.

Out of the 53% of snoopers that found incriminating evidence on their partner’s phone, 5% went on to terminate their relationship.

Waterproof mobile phones came to market because Japanese youngsters like to use them in the shower.

Apparently mobile phones have 18 times more bacteria on them than toilet handles!

Phubbing describes the act of snubbing someone by using your mobile phone in their company.

In 2015 more people died from taking selfies than shark attacks.

Teenagers that use a phone more than 2 hours a day increase their risk of depression and anxiety.

Nomobophobia is severe anxiety caused by the thought or act of losing your phone or running out of battery.

Explanation:

6 0

2 years ago

Read 2 more answers

One kilogram of a contaminant is spilled at a point in a 4m deep reservoir and is instantaneously mixed over the entire depth. (

rosijanka [135]

Answer:

0.028 kg per Seconds; 8.4

Explanation:

N-S, 4 x 100 = 400 m^2, concentration 5/400= 0.0125 kg/s

E-W 4 x 100 =400 m^2 , => 10/400 =0.025 kg/s

(0.0125^2 + 0.025^2)^(1/2) =0.028 kg/s

in 5 minutes = 5 x 60 x 0.028 =8.4

8 0

3 years ago