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nadezda [96]
3 years ago
8

What is the purpose of a rearview mirror in a car?

Physics
3 answers:
Maslowich3 years ago
8 0
It is called rearVIEW mirror so

ans is <span>The mirror allows the light to be reflected so the objects behind the car can be seen.</span>
Shalnov [3]3 years ago
5 0
The third choice.

The driver wants to see the object that is behind him. The light reflects off the mirror into the eyes of the driver portraying the object behind him
ratt3 years ago
0 0

C: The mirror allows the light to be reflected so the objects behind the car can be seen.

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A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?
san4es73 [151]
Find 10 % of 50,000 = 5000
double it to make 10000
add on to 50000 to make 60000
60000 is your answer
6 0
3 years ago
A boy whirls a ball on a string in a horizontal circle of radius 1 m. How many revolutions per minute must the ball make if its
spayn [35]

Answer:

Nearest, the revolutions per minute will be 29.

Explanation:

Given that,

Radius of circle = 1 m

Acceleration a =g

We know that,

Angular frequency is defined as,

\omega=2\pi n

Where, n = number of revolutions in one second

We need to calculate the revolutions in one second

Using formula of centripetal acceleration

a=\omega^2r

Put the value of a and ω

g=(2\pi n)^2r

n=\sqrt{\dfrac{g}{r}}\times\dfrac{1}{2\pi}

Put the value into the formula

n=\sqrt{\dfrac{9.8}{1}}\times\dfrac{1}{2\pi}

n=0.49

We need to calculate the revolutions per minute

Using value for the revolutions per minute

n=0.49\times60

n=29.4

Hence, Nearest, the revolutions per minute will be 29.

7 0
3 years ago
Which is more work, pushing with 115 N over 15m or lifting 20N over 10 m?
Nikitich [7]

Work = (force) x (distance)

You could look at the two cases, and see right away that
the first one has more force acting through more distance,
so it must be more work.  But since I just gave you the formula
for Work, let's calculate the amount of it for both cases:

First case:  Work = (115 N) x (15 m) =   1,725 joules

Second case:  Work = (20 N) x (10 m)  =  200 joules

The first case involves 8.625 times as much work as the second case.

3 0
3 years ago
Read 2 more answers
What type of energy dose an earthquake transfer
IrinaVladis [17]
Earthquakes release energy in several forms: The energy in seismic waves that cause the ground to shake. Heat energy associated with friction on the fault slip surface. Gravitational potential energy (the energy stored when lifting something off the ground, for example) may change as a result of the earthquake.
7 0
3 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 19.0 ∘ west of north,
valina [46]

Answer:

=2.99\times10^9J

Explanation:

According to the question

net force F = 2.20×10^6 N

displacement S = 0.72\times10^3m

from figure , the horizontal forces are same in magnitude and opposite direction.

so , neglect these two forces.

we can take only vertical components of the force.

total force F' = F cos 19° + F cos 19°

= 2×F×cos 19°   ................. (1

therefore , total work is

W = F'S

= (2F cos19)×S

= (2)(2.20\times10^6 N)cos19° (0.720\times10^3 m)

=2.99\times10^9J

6 0
3 years ago
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