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Aliun [14]
3 years ago
12

In the absence of air, a penny and a feather dropped from the same height will

Physics
2 answers:
Roman55 [17]3 years ago
7 0
When they are dropped at the same height, taking their mass into account, the feather will touch the ground last.
kotykmax [81]3 years ago
6 0
The feather will touch the ground last, because it has a lighter mass. Hope it helps!
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A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of
levacccp [35]

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
3 0
1 year ago
Aiden takes 0.10s to throw a baseball, which leaves his hand with a velocity of 49m/s. The balls acceleration is
Brums [2.3K]
Since the ball was not moving before it let Aiden's hand, the formula used to calculate the acceleration is
a =  \frac{v}{t}
, where a is acceleration, v is velocity and t is the time. We put them in the formula and get
a =  \frac{49}{0.1}  \\ a =  \frac{490}{1}  \\ a = 490
The acceleration is 490 m/s^2
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3 years ago
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liq [111]
How do I make a question help PLZZZ
5 0
3 years ago
In 1 to 2 sentences explain how you would determine the constant K for a spring
Olin [163]

When spring times comes around you ever be like, "k." If you feel like that every year during spring then there you go

8 0
3 years ago
Which statement describes the relationship between energy and entropy in the universe?
rusak2 [61]

In fact, entropy of an isolated system never decreases (2nd law of thermodynamics), unless some external energy is provided in order to "restore" order in the system and decrease its entropy.

(note that when external energy is added to the system, it is no longer "isolated").


*This is only true if the question is referring to a certain system within the universe. If we are considering the universe itself as the system, then this option is no longer correct, because no external energy can be provided to the universe, and since the universe is an isolated system, its entropy can never decrease. If we are considering the universe itself as the system, none of the options is true.




8 0
3 years ago
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