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4 years ago

What is the ratio of the sun's gravitational force on you to the earth's gravitational force on you? fsunfearth =?

1 answer:

8 0

<span>The ratio of the sun's gravitational force on us to the earth's gravitational force on us is 6.0 * 10^-4.This is a result of the formula Fg= G*(m/r^2), where G is the gravitational Constant = 6.67*10^-11. m = mass and r = radius</span>

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Sphere x, of mass 2 kg, is moving to the right at 10m/s. sphere y, of mass 4 kg, is moving to the left at 10m/s. the two spheres

Neporo4naja [7]

20m/s, honestly I have know idea what the asnwer is but if i had to guess, this would be my answer.

6 0

4 years ago

light traveling through air encounters a second medium which slows the light to 100,000 miles/second. What is the index of the s

IceJOKER [234]

Answer:

300000 hope it is help full

Explanation:

300000

6 0

2 years ago

Read 2 more answers

A grocery shopper tosses a(n) 9.4 kg bag of rice into a stationary 19.9 kg grocery cart. The bag hits the cart with a horizontal

IRINA_888 [86]

The final speed of the cart and the bag is 2.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the bag and the cart must be conserved before and after the collision.

Mathematically:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 9.4 kg$ is the mass of the bag of rice

$u_1 = 7.0 m/s$ is the initial velocity of the bag

$m_2 = 19.9 kg$ is the mass of the cart

$u_2 =0 m/s$ is the initial velocity of the cart (at rest)

$v$ is the final combined velocity of the bag and the cart

Re-arranging the equation and solving for v, we find:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(9.4)(7.0)+0}{9.4+19.9}=2.2 m/s$

Learn more about momentum here:

brainly.com/question/7973509

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3 years ago

When a comet is within the inner solar system, its visible tails point __________.

astraxan [27]

away from the sun

hope it helps...!!!!

6 0

2 years ago

Chegg ) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m(t)

stepladder [879]

Answer:

$m(t)=20e^{-0.5t}$

Explanation:

Given:

Initial mass of isotope (m₀) = 20 g

Half life of the isotope $(t_{1/2})$ = (ln 4) years

The general form for the radioactive decay of a radioactive isotope is given as:

$m(t)=m_0e^{-kt}$

Where,

$m(t)\to mass\ after\ 't'\ years\\t\to years\ passed\\k\to rate\ of\ decay\ per\ year$

So, the equation is: $m(t)=20e^{-kt}$

At half-life, the mass is reduced to half of the initial value.

So, at $t=t_{1/2},m(t)=\frac{m_0}{2}$ . Plug in these values and solve for 'k'. This gives,

$\frac{m_0}{2}=m_0e^{-k\times\ln 4}\\\\0.5=e^{-k\times\ln 4}\\\\Taking\ natural\ log\ on\ both\ sides,we\ get:\\\\\ln(0.5)=-k\times \ln 4\\\\k=\frac{\ln 0.5}{-\ln 4}=0.5$

Hence, the equation for the mass remaining is given as:

$m(t)=20e^{-0.5t}$

8 0

4 years ago