In the above diagram, the block is at static equilibrium on the ground. What is the value of the force exerted by the ground on
the block if the force due to gravity is 12 newtons?
A. 20 newtons
B. 12 newtons
C. -12 newtons
D. -20 newtons
E. 0 newtons
A. 20 newtons
B. 12 newtons
C. -12 newtons
D. -20 newtons
E. 0 newtons
1 answer:
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Answer:
Lowest frequency that gives the minimum signal is 343 Hz
lowet frequency for maximum signal 686 Hz
Explanation:
D_1 = 2.00 m
D _2 =3.75 m
Δx =
=
= 0.5 m
for minimum distructive interference, the path difference is
Δx =
for minimum n = 0
= 2*0.5 = 1 m
lowest frequency f =
where c is speed of sound in air 343 m/s
b) lowet frequency for maximum signal
for minimum CONSTRUCTIVE interference, the path difference is
Δx =
for minimum n = 1
= 0.5 m
lowest frequency f =
f =
The period of the planet is 58.1 years
Explanation:
We can solve this problem by using Kepler's third law, which states that:
"The square of the orbital period of a planet is proportional to the cube of its semimajor orbital axis"
Translated into equations, we can write:
Where, taking the orbits of the planets as almost circular, we have:
is the orbital period of the unknown planet
is the radius of the orbit of the planet
(1 year) is the period of the orbit of the Earth
is the orbital radius of the Earth
Solving for , we find the orbital period of the unknown planet:
Learn more about Kepler's third law:
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