The focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.
<h3>Focal length</h3>
The focal length, f is the distance from a lens or mirror to the focal point, F.
This is the distance from a lens or mirror at which parallel light rays will meet for a converging lens or mirror or appear to diverge from for a diverging lens or mirror.
A magnifying glass is a converging lens which produces a enlarged, erect and virtual image when an object is placed between the focal point and optical centre.
A magnifying glass will bring to focus at a point sun rays which can cause the paper to catch fire if it is held in place for long.
This point at which the most concentrated ray of light is shining on the paper, is the focal point for that magnifying glass.
Therefore, the focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.
Learn more about about focal length at: brainly.com/question/25779311
True a proton carries a positive charge, a neutron carries a neutral charge and an electron carries a negative charge.
Answer:
- <u>verbal,</u>
- <u> Intrapersonal</u>
Explanation:
Remember, we are told that "Professor Wooddro<em> </em><em>teaches an Introduction to Philosophy at the college, and loves to talk about the meaning of life and death"</em> which would require having verbal intelligence (the ability to understand and relate information using words).
Intrapersonal intelligence is also reflected by Professor Wooddro as we are told he "enjoys struggling with life's most challenging questions", <u>which shows his knowledge of his own strengths or weaknesses.</u>
Answer:
a)Amplitude ,A = 2 mm
b)f=95.49 Hz
c)V= 30 m/s ( + x direction )
d) λ = 0.31 m
e)Umax= 1.2 m/s
Explanation:
Given that
As we know that standard form of wave equation given as
A= Amplitude
ω=Frequency (rad /s)
t=Time
Φ = Phase difference
So from above equation we can say that
Amplitude ,A = 2 mm
Frequency ,ω= 600 rad/s (2πf=ω)
ω= 2πf
f= ω /2π
f= 300/π = 95.49 Hz
K= 20 rad/m
So velocity,V
V= ω /K
V= 600 /20 = 30 m/s ( + x direction )
V = f λ
30 = 95.49 x λ
λ = 0.31 m
We know that speed is the rate of displacement
The maximum velocity
Umax = 1200 mm/s
Umax= 1.2 m/s