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slamgirl [31]
3 years ago
7

A 5 kw solar energy system can collect 9000 kwh of energy per year. Arizona electricity is .011 cent per kilowatt hour. The aver

age Arizona home uses 66 million btu per year. Given that 1 btu= 0.000293 kwh find the number of kilowatt hours used by the average home in Arizona in a given year.
B. How much does a typical Arizonan homeowner spend on electricity per year?

C. If a typical Arizona household were to install a 5 kw solar system, how much would it save on electricity per year?

D. Given that the 5 kw system would cost $20,000 to install (minus a 30% federal tax credit) how many years would it take to recoup the initial investment?
Mathematics
1 answer:
alexira [117]3 years ago
4 0
I don’t know but I think it’s dim guess
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What is the domain of h?
iren2701 [21]

Answer:

its actually D :0

Step-by-step explanation:

7 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
2 years ago
PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Bond [772]

Answer:

R = \frac {3ST}{2S + T}

Step-by-step explanation:

Given the equation;

\frac {3}{R} - \frac {1}{S} = \frac {2}{T}

Rearranging the equation, we have;

\frac {3}{R} = \frac {2}{T} + \frac {1}{S}

Lowest common multiple (LCM) of S and T is ST.

\frac {3}{R} = \frac {2S + T}{ST}

Cross-multiplying, we have;

3ST = R(2S + T)

Making R, the subject of formula;

R = \frac {3ST}{2S + T}

8 0
3 years ago
In an experiment you do a chi-square test comparing observed and expected progeny. Your calculated chi square is 0.375. With 1 d
myrzilka [38]

Answer:

It mean that the observed progeny is similar than the expected progeny. There is no a relationship between the categorical variables.

Step-by-step explanation:

The Chi-squared test is used to test the relationship between categorical variables. A categorical variable is a non-numerical variable. The null hypothesis of the Chi-squared test is that categorical variables are independent; it means that the frequencies are not dependent on the variable. It is important to know that the Chi-squared test does not measure causality, it only measures the relationship. To reject the null hypothesis, you usually need a probability lower than 0.05, but in this case, the probability was way higher than 0.05, it was between 0.5 and 0.9.

4 0
3 years ago
If andy pays 450 of the rent and mo pays 1/2 of the rent and charlie pays 25percent of the rent what is the overall rent
scoray [572]

Answer:

$1,800

Step-by-step explanation:

If Mo pays 1/2 of the rent then he is paying 50%. Charlie is paying another 25%. This leaves the remaining 25% that Andy pays. Since Andy's payment amount is 450 then that means that 450 is equal to 25% of the total rent. Therefore, we simply need to multiply this amount by 4 to get the 100% of the overall rent.

450 * 4 = $1,800

Finally, we can see that the total rent amount is $1,800

4 0
2 years ago
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