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Irina18 [472]
3 years ago
6

within what force will acar hit a tree if the car has a mass of 3,000 kg and it is accelerating at a rate of 2 m/s/s

Physics
1 answer:
alexdok [17]3 years ago
7 0
Use the formula. Plug in known values, so you get f = 3000*2 and get 6000N as a result. 
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The velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration​
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Answer:

acceleration = v-u/ t

= 15-10/5

= 5/5

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Explanation:

hope this helped you.

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A bird flies north 3 kilometers and then south 4 kilometers, what is the resultant displacement of the bird? Do not forget to in
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2 years ago
h(t) = - 16t2 + 64t + 112 where t is the time in seconds. After how many seconds does the arrow reach it maximum height? Round t
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2 seconds

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The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.

h(t)=-16t^{2}+64t+112

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8 0
3 years ago
If a pedestrian walked 900 meters forward and 300 meters back
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B

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2 years ago
In the diagram, q1 = +6.60*10^-9 C and q2 = +3.10*10^-9 C. Find the magnitude of the total electric field at point P. pls help?
kirza4 [7]

Answer:

|E(t)| = 1258,46 [N/C]

α = 67,5⁰  (angle with respect x-axis)

Explanation:

E(t)  Electric Field is a vector, so we need to determine module and direction

E(t)  =  E(q₁)  + E (q₂)  Where E(q₁) and E (q₂) are electric fields due to electric charge q₁ and q₂  respectively.

E(q₁) = K * q₁/ (d₁)²         K = 9 *10⁹   [N*m²/C²]    d₁ = 0,350 m

E(q₁) = 9 *10⁹ * 6,6*10⁻⁹ / 0,1225      [N*m²/C²] *C/m²

E(q₁) = 484,9 [N/C]

E(q₂) =  9 *10⁹ * 3,1*10⁻⁹ / 0,024025

E(q₂) = 1161,29

Then

|E(t)| = √ |Eq₁|² + |Eq₂|²

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|E(t)| = √ 235128 + 1348594,46

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And tanα = 1161,29/484,9        tanα =  2,395      α = 67,5⁰

The angle of the vector electric field with the x-axis

3 0
3 years ago
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