Ask question

Ask question

All categories

3 years ago

6

within what force will acar hit a tree if the car has a mass of 3,000 kg and it is accelerating at a rate of 2 m/s/s

1 answer:

alexdok [17]3 years ago

7 0

Use the formula. Plug in known values, so you get f = 3000*2 and get 6000N as a result.

You might be interested in

A 500 gram mass attached to a horizontal spring

Daniel [21]

Is that a question? .
..............................

8 0

3 years ago

Need some help with this!

zvonat [6]

Answer: what’s it asking

Explanation:

8 0

3 years ago

Read 2 more answers

A. Which of the four thermal processes describes the pressure-volume relationship at a constant temperature?

lara31 [8.8K]

The thermal process that occurs when pressure and volume are variable, while the temperature remains constant is known as an isothermal process. Due to the change in temperature being zero, the internal energy of the system does not change. Isothermal processes can be carried out adiabatically or non-adiabatically. (An adiabatic process is where the heat energy moving through the boundary of a system is 0)

4 0

3 years ago

What is the meaning of coulomb in physics ????

julia-pushkina [17]

Coulomb, unit of electric charge in the metre-kilogram-second-ampere system, the basis of the SI system of physical units. ... The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.

Mark me as brainliest....

4 0

2 years ago

A small plane flies 40.0 km in a direction 60° north of east and then flies 30.0 km in a direction 15° north of east. Use the an

lana66690 [7]

Answer:

d= 64.7 km

$\theta = 40.9^{o}$

displacement vector $=r_xi + r_yj = 48.9i + 42.4j$

Explanation:

total distance = 40 + 30 = 70 km

during 1st flight

$r_1 x = 40*cos60$

$r_1 x = 20 km$

$r_1 y = 40*sin60$

$r_1 y = 34.64 km$

during 2nd flight

$r_2 x = 30*cos15$

$r_2 x = 28.9 km$

$r_2 y = 30*sin15$

$r_2 y = 7.76 km$

the two component of r are:

$r_x = r_1x + r_2x = 20 + 28.9 = 48.9 km$

$r_y = r_1y + r_2y = 34.64 + 7.76 = 42.4 km$

Geographical Direction $\theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}$

Displacement d $= \sqrt{r_x^2 + r_y^2}$

$d = \sqrt{48.9^2+42.4^2} = 64.7 km$

d= 64.7 km

displacement vector $=r_xi + r_yj = 48.9i + 42.4j$

8 0

3 years ago