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Elis [28]
2 years ago
6

What is 11.7 times 11.7

Mathematics
2 answers:
earnstyle [38]2 years ago
7 0

Answer:

136.89

Step-by-step explanation:

Mazyrski [523]2 years ago
4 0

Answer:

136.89

Step-by-step explanation:

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During a game, players can win and lose counters. At the start of the game
Mademuasel [1]
The first step is to calculate what fraction of the counters that Rob has.

Add all the portions together to find the total: 5+6+7= 18
Rob has 5 out of the 18, or 5/18, or 0.278

Next, do the same for the end ratio:
7+9+8= 24 and Rob has 7/24, or 0.292

By comparing his beginning portion (0.278) to his end portion (0.292) it is clear that he has a greater portion of the total counters. Given that the problem states that the number of counters stays the same, Rob must have more counters than he started with.
5 0
3 years ago
If 42 pushups is done in 3 minutes how many can be done in 5
tresset_1 [31]
So first find out how many can be done in 1 minute.
In an equation it would be 3x=42
Divide by 3
x=14
So 14 pushups can be done in 1 minute (congratulations to this person I can barely do one haha)
So now you multiply what you can do in 1 minute by 5 minutes.
14x5= 70 pushups
4 0
3 years ago
He weighs 88.9kg.how many gram is this
Thepotemich [5.8K]
1 kg= 1000 gram
88.9 kg= 88.9 x 1000
=88,900 gram
8 0
3 years ago
A survey was conducted of 42 students who take math, Eng lish, or history. In the survey, 15 students said they take math and hi
strojnjashka [21]

Answer:

16 students take only English or only Math.

Step-by-step explanation:

We can solve this problem by treating these values as sets, and building the Venn Diagram.

I am going to say that:

A is the number of students who take Math.

B is the number of students who take English.

C is the number of students who take History.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only take Math, A \cap B is the number of students who take both Math and English, A \cap C is the number of students that take both Math and History, and A \cap B \cap C is the number of students that take all these classes.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There were 42 students suveyed. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

We start finding the values from the intersection of three sets.

12 students said they take math, English, and history. This means that:

A \cap B \cap C = 12

18 students said they take English and history. This also takes into account those who take math, english and history. So:

(B \cap C) + (A \cap B \cap C) = 18

B \cap C = 6

17 students said they take math and English.

(A \cap B) + (A \cap B \cap C) = 17

A \cap B = 5

15 students said they take math and history

(A \cap C) + (A \cap B \cap C) = 15

A \cap C = 3

2 students said they only take history.

c = 2

How many students take only English or only math?

This is a + b, that we can find by the following formula:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

a + b + 2 + 5 + 3 + 6 + 12 = 42

a + b = 16

16 students take only English or only Math.

4 0
3 years ago
Which expressions are difference of squares?
cluponka [151]

Answer:

x² - y² and x^4 - 36

Step-by-step explanation:

(x + y)(x - y)

(x² + 6)(x² - 6)

6 0
3 years ago
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