Explanation:
the object will begin to move
The angular acceleration of the blade when it's switched off is (-6800 rev/min) divided by (2.8 sec) = -2,428.6 rev/(min-sec) = -40.5 rev/sec^2 .
The De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°
<h3>How is the De broglie wavelength of a thermal neutron at room temperature calculated?</h3>
Temperature, T = 300K
Momentum, p = mv
Therefore v = p/m
Energy, E= 1/2 m( p/m) ²
Boltzman Energy= 3/2 KT
3/2KT = 1/2 m(p/m)²
Therefore p =
According to De broglie hypothesis, P = h ÷ λ
Therefore, λ = h ÷ 
= 6.6×
÷ 
= 0.15 × 
Therefore the De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°
To learn more about De broglie wavelength, refer: <u>https://brainly.in/question/6131028</u>
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Answer:
id say D
Explanation:
because its the only answer that has to do with colors and visable light
but A and B also have to do with eachother so i feel like it could be with one of those but it def isnt C
I am sorry if i am wrong, let me know tho!