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Rufina [12.5K]
3 years ago
8

Does sound travels through your skull to your ear when you speak ? If yes then how ?

Physics
1 answer:
Maksim231197 [3]3 years ago
5 0
Sound travels through waves, more specifically, through vibrations. They do not go from skull to ear, but they can go from ear to brain, or skull to brain. Ear to brain is simply vibrations traveling from outer ear, to inner ear, to the brain. Skull to brain, otherwise known as "bone conduction", has the vibrations hitting the skull, then to the temproal bone, then to the inner ear where the brain picks it up.
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A professional cyclist rides a bicycle that is 92 percent efficient. For every 100 joules of energy he exerts as input work on t
emmainna [20.7K]
Efficiency =  Work Output / Work Input

92%  =  Work Output / 100

0.92 =   Work Output / 100

Work Output = 0.92 * 100

Work Output  = 92 joules.
8 0
3 years ago
Which type of surface would most likely be the best reflector of electromagnetic energy?
Len [333]
<span>light colored and smooth surface would most likely be the best reflector of electromagnetic energy.Light, shiny surfaces are the best reflectors of radiation and they will allow the waves to reflect and bounce off rather than absorb. we can consider mirror as the example ,it will only reflect the light energy falling on them and it will not absorb. The darker coloured and rough surfaced substances will definitely absorb some amount of light falling on it. so light coloured smooth or shiny surfaced material would be the best reflector for electromagnetic energy.</span>
5 0
3 years ago
A student releases a block of mass m at the top of a slide of height h1. the block moves down the slide and off the end of the t
Virty [35]

Answer:

B)   d = √  ( 4 h₂ ( H - 2h₂))

Explanation:

A) 1) If the height of the slide is very small, there is no speed to leave the table, therefore do not recreate almost any horizontal distance

2) If the height is very small downwards, it touches the earth a little and the horizon is small,

B) to find an equation for horizontal distance (d)

We must maximize the speed at the bottom of the slide let's use energy

Starting point Higher

          Em₀ = U = m g h₁

Final point. Lower (slide bottom)

            Emf = K + U = ½ m v² + m gh₂

As there is no friction the energy is conserved

             mgh₁ = ½ m v² + mgh₂

             v² = 2 g (h₁-h₂)

This is the speed with which the block leaves the table, bone is the horizontal speed (vₓ)

The distance traveled when leaving the table can be searched with kinematics, projectile launch

           x = v₀ₓ t

          y = v_{oy} t - ½ g t²

The height is the height of the table (y = h₂), as it comes out horizontally the vertical speed is zero

         t = √ 2h₂ / g

We substitute in the other equation

         d = √ (2g (h₁-h₂))  √ 2h₂ / g

         d = √ (4 h₂ (h₁-h₂))

         H = h₁ + h₂

         h₁ = H -h₂

         d = √  ( 4 h₂ ( H - 2h₂))

3 0
3 years ago
Read 2 more answers
Clyde and Marilyn are riding a roller coaster. During which section of the track is their potential energy converted to kinetic
Alex17521 [72]

Potential energy is when the roller coaster rises. Kinetic energy is when the roller coaster declines.

5 0
3 years ago
In the year 2055, a rocket was launched from a research laboratory on Mars. Mars has essentially no atmosphere. The test rocket
algol [13]

Answer:

h = 618.64 m

Explanation:

First we need to calculate the height gained by rocket while the fuel is burning. We use 2nd equation of motion for that purpose:

h₁ = Vit + (1/2)at²

where,

h₁ = height gained during the burning of fuel

Vi = Initial Velocity = 0 m/s

t = time = 7 s

a = acceleration = 8 m/s²

Therefore,

h₁ = (0 m/s)(7 s) + (1/2)(8 m/s²)(7 s)²

h₁ = 196 m

Now we use 1st equation of motion to find final speed Vf:

Vf = Vi + at

Vf = 0 m/s + (8 m/s²)(7 s)

Vf =  56 m/s

Now, we calculate height covered in free fall motion. Using 3rd equation of motion:

2ah₂ = Vf² - Vi²

where,

a = - 3.71 m/s²

h₂ = height gained during free fall motion = ?

Vf = Final Velocity = 0 m/s (since, rocket will stop at highest point)

Vi = 56 m/s

Therefore,

(2)(-3.71 m/s²)h₂ = (0 m/s)² - (56 m/s)²

h₂ = 422.64 m

So the total height gained will be:

h = h₁ + h₂

h = 196 m + 422.64 m

<u>h = 618.64 m</u>

4 0
3 years ago
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