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3 years ago

Which elements are halogens check all that apply

Physics

2 answers:

Usimov [2.4K]3 years ago

5 0

the halogens is group 17,,

aniked [119]3 years ago

4 0

The answer is : the halogens are group 17

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Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 2.4

NeX [460]

When person is observing destructive interference at 0.20 m distance from the equidistant position then we can say that path difference must be equal to half of the wavelength

now we will have

$\frac{\lambda}{2} = \frac{yd}{L}$

now we know that

y = 0.20 m

d = 2.4 m

L = 10 m

now here we have

$\frac{\lambda}{2} = \frac{0.20\times 2.4}{10}$

$\lambda = 0.096 m$

now frequency of wave is given as

$f = \frac{v}{\lambda}$

$f = \frac{343}{0.096} = 3573 Hz$

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3 years ago

20. There are two electrical devices, one is electrical kettle of 2KW-200V and

RUDIKE [14]

Electrical kettle:

P = 2 KW = 2000 W

U = 200 V

⇒ I = P/U = 2000 / 200 = 10 A

We apply the Law of Ohm:

R = U / I = 200V / 10A = 20 Ω

=======

Electrical heater:

P = 1 KW = 1000 W

U = 240 V

⇒ I = P/U = 1000 / 240 = 4,16 A

We apply the Law of Ohm:

R = U / I = 240V / 4,16A = 57,69 Ω

Answer:

The device with the highest resistance is the electric heater.

6 0

4 years ago

You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound

san4es73 [151]

Answer:

$d = 343 m$

Explanation:

As we know that the speed of sound in air is given as

$v = 343 m/s$

now the rate of strike is 1 stroke per second

so distance is given as

$d = v t$

now we will have

$t = 1 s$

$d = 343 \times 1$

so the distance is given as

$d = 343 m$

5 0

3 years ago

you place a one-liter substance in a 2-liter bottle and tightly cover the bottle. the substance expands until it completely fill

9966 [12]

Answer:

The substance in is at state of gas.

Explanation:

Please see attavhed document

Download docx

4 0

2 years ago

A small rock is thrown vertically upward with a speed of 27.0 m/s from the edge of the roof of a 21.0-m-tall building. The rock

lbvjy [14]

Answer:

A. 33.77 m/s

B. 6.20 s

Explanation:

Frame of reference:

Gravity g=-9.8 m/s^2; Initial position (roof) y=0; Final Position street y= -21 m

Initial velocity upwards v= 27 m/s

Part A. Using kinematics expression for velocities and distance:

$V_{final}^{2}=V_{initial}^{2}+2g(y_{final}-y_{initial})\\V_{f}^{2}=27^{2}-2*9.8(-21-0)=33.77 m/s$

Part B. Using Kinematics expression for distance, time and initial velocity

$y_{final}=y_{initial}+V_{initial}t+\frac{1}{2} g*t^{2}\\==> -0.5*9.8t^{2}+27t+21=0\\==> t_1 =-0.69 s\\t_2=6.20 s$

Since it is a second order equation for time, we solved it with a calculator. We pick the positive solution.

8 0

3 years ago