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3 years ago

Cooking chicken in a oven is physical change or chemical change

Chemistry

1 answer:

Nady [450]3 years ago

4 0

Chemical change because it is going through chemical properties when heated.

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What is the classification of a solution of naoh with a ph of 8.3?

Maksim231197 [3]

Answer:

Alkaline or basic solution (alkaline and basic means the same)

Explanation:

According to the pH, solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH classification

7 neutral

> 7 alkaline or basic

< 7 acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

$pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501$

NaOH solutions are alkaline solutions, bases, according to Arrhenius model, because they contain OH⁻ ions and release them when ionize in water.

8 0

2 years ago

Which of the following elements has the largest ionization

Tanya [424]

shdhdjrbfjfbrkdbdkdbdjdbriebdj

8 0

2 years ago

1.The movement of particles from a less crowded area to a more crowded area requires

Harrizon [31]

1. Energy as particles can't move without kinetic (movement) energy
2. I think it's Diffusion and Active Transport

7 0

3 years ago

You have a solution that is 0.02M formate (HCOO-) and 0.03M formic acid (HCOOH), which has a Ka of 1.8x10-4. What is the pH of t

lisov135 [29]

Answer:

3.6

Explanation:

Step 1: Given data

Concentration of formic acid: 0.03 M

Concentration of formate ion: 0.02 M

Acid dissociation constant (Ka): 1.8 × 10⁻⁴

Step 2: Calculate the pH

We have a buffer system formed by a weak acid (HCOOH) and its conjugate base (HCOO⁻). We can calculate the pH using the Henderson-Hasselbach equation.

$pH = pKa +log\frac{[base]}{[acid]} = -log 1.8 \times 10^{-4} + log \frac{0.02}{0.03} = 3.6$

6 0

2 years ago

What volume of 7.68 M NaOH (aq) will neutralize 1.15 L of 2.35 M H2SO4 (aq) ?

aleksklad [387]

Answer:

hmm lemme think bur it will take a while

8 0

2 years ago