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aleksandrvk [35]
4 years ago
5

What precipitate is most likely formed from a solution containing ca2+, na+, oh−, and co2−3. what precipitate is most likely for

med from a solution containing , , , and . naoh caco3 na2co3 ca(oh)2?
Chemistry
2 answers:
Dimas [21]4 years ago
8 0

The solution contains four ions

Ca2+, Na+, OH−, and CO3^-2

so there are following four combinations are possible

NaOH : this is highly soluble in water so will not form precipitate

Ca(OH)2: this is highly soluble in water so will not form precipitate

Na2CO3: again soluble in water so will not form precipitate

CaCO3 : this is not soluble in water (it has low solubility product) so this will form precipitate most likely


STatiana [176]4 years ago
6 0
The compounds that can be formed by using only the cations and anions found in the item above are as follows: (1) Ca3(CO2)2, Na3CO2, NaOH, Ca(OH)2

The last two in the given are in aqueous phase. We are then left with the first two choices. Ca3(CO2)2 is exhibits a phase that is in solid form. 

Hence, the answer to the question is Ca3(CO2)2
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A gas occupies 50.0mL at a standard temp. What volume would it occupy at 335 Celsius with
tino4ka555 [31]

Answer:

V₂ = 111.3 mL

Explanation:

Given data:

Initial volume of gas = 50.0 mL

Initial temperature = standard = 273.15 K

Final volume = ?

Final temperature = 335 °C (335+273.15 = 608.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0  mL ×608.15 K / 273.15 k

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V₂ = 111.3 mL

7 0
3 years ago
Which is NOT a property of metals?
frutty [35]
C is not a property of metals
3 0
4 years ago
2 A certain gas of 25 g at 25°c and 0.65 atm occupies a volume of 23.52L Determine the molecule mass of the gas.​
denpristay [2]

Answer:

{ \bf{PV= \frac{m}{M} RT}} \\  \\ { \tt{(0.65  \times 23.52)  =  \frac{25}{M}  \times 0.081 \times (25 + 273)}} \\  \\ M = 39.5 \: g

8 0
3 years ago
1. Which form of sanitation do health experts prefer, washing hands with soap and water or
geniusboy [140]

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5 0
3 years ago
How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
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