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lbvjy [14]
2 years ago
13

Plutonium-239 undergoes alpha decay and has a half-life of 24,000 years. After 72,000 years, how much of an initial 100.0 g samp

le will remain?
A. none
B. 50.0 g
C. 25.0 g
D. 12.5 g
Chemistry
1 answer:
dybincka [34]2 years ago
8 0
After 72000 years, the half life would have passed 3 times.

This means that (1/2)^3 = 1/8 of the original sample would remain.

The original sample is 100.0 g, meaning that 1/8 of the sample would be 12.5 g.

So, the answer is D.
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A container of hydrogen at 172 kPa was decreased to 85.0 kPa producing a new volume of 3L. What was the original volume?
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Answer:

<h2>The answer is 1.48 L</h2>

Explanation:

In order to find the original volume we use the same for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the original volume

V_1 =  \frac{P_2V_2}{P_1}  \\

From the question

P1 = 172 kPa = 172000 Pa

P2 = 85 kPa = 85000 Pa

V2 = 3 L

We have

V_1 =  \frac{85000 \times 3}{172000}  =  \frac{255000}{172000}  =  \frac{255}{172}  \\  = 1.482558139...

We have the final answer as

<h3>1.48 L</h3>

Hope this helps you

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