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ioda
4 years ago
11

5. Haley throws her ball downward with speed v from height 2h. Simultaneously, Joe drops his ball from rest at height h. What sh

ould v be so that the two balls hit the ground at the same time
Physics
1 answer:
Aneli [31]4 years ago
3 0

Answer:

We know that the second equation of motion is

S= ut + 1/2a²

And S is displacement and u is initial velocity

So in the case of Haley lets take downwards as positive Y-axis

S = 2h and

initial velocity = v

a = g (acceleration due to gravity = 9.8)

Substituting

2h = vt + 1/2gt²

And for Joe we take ownwards as positive Y-axis

S = h and

initial velocity = 0 (since the ball is dropped from rest)

a = g

h = 0x t + 1/2gt2²

t2= √ 2h/g

Now since both balls reach ground at same time: t1=t2

So

putting value of t2 in Hayley's equation:

2h= v(√2h/g) + 1/2 g( √2h/g)²

So v= √gh/2

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Energy

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3 years ago
In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushion
Leno4ka [110]

Answer:

4 m/s²

Explanation:

 When the elevator is 1 m below point of contact , compression will be 1 m.

Restoring force in the spring will be 10600 N. Friction force of 17000N  will also act in upward direction . The weight of 2000 x 9.8 N will act downwards

Force in down ward direction = 2000 x 9.8

= 19600 N

Force in upward direction

= 10600 + 17000

= 27600 N

Net force in upward direction

= 27600 - 19600

= 8000 N

Acceleration in upward direction

= 8000 / 2000

= 4 m/s²

5 0
4 years ago
Consider the interference pattern produced by two parallel slits of width a and separation d, in which d = 3a. The slits are ill
laila [671]

Answer:

a)   m =1  θ = sin⁻¹  λ  / d,  m = 2        θ = sin⁻¹ ( λ  / 2d) ,   c)     m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

         d sin θ = m λ

the maximum for m = 1 is at the angle

          θ = sin⁻¹  λ  / d

the second maximum m = 2

          θ = sin⁻¹ ( λ  / 2d)

the third maximum m = 3

        θ = sin⁻¹ ( λ  / 3d)

the fourth maximum m = 4

       θ = sin⁻¹ ( λ  / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

       I = I₀ cos² (Ф) (sin x / x)²

       Ф = π d sin θ /λ

       x = pi a sin θ /λ

where a is the width of the slits

with the values ​​of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference       d sin θ = m λ

first diffraction minimum    a sin θ = λ

we divide the two expressions

                       d / a = m

In our case

                   3a / a = m

                    m = 3

order three is no longer visible

7 0
3 years ago
A football player kicks a 0.94 kg football with a force of 2.4 N.
Artyom0805 [142]

2.6m/s²

Explanation:

Given parameters:

Mass of football = 0.94kg

Force on ball = 2.4N

Unknown:

The acceleration of the ball = ?

Solution:

According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

  Net force = mass x acceleration

Make acceleration the subject of the expression;

       Acceleration = \frac{net force}{mass}

Acceleration  = \frac{2.4}{0.94}  =  2.6m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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