We attach two blocks of masses m1 = 7 kg and m2 = 7 kg to either end of a spring of spring constant k = 1 N/m and set them into
1 answer:
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Answer:
<h3>The answer is 0.59 m/s²</h3>Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>0.59 m/s²</h3>Hope this helps you
Answer:
Her speed at the bottom of the slope is 25.665 m/s
Explanation:
Here we have
Initial velocity, v₁= 15 m/s
Final velocity = v₂
The energy balance present in the system can be represented as
Where:
m = Mass of the cyclist = 70 kg
W = work done by the drag force =
Where:
d = Distance traveled = 450 m
Therefore,
and
= 658.714 m²/s²
v₂ = 25.665 m/s
Her speed at the bottom of the slope = 25.665 m/s.
Answer:
0.779 mol
Explanation:
Since the gas is in a bottle, the volume of the gas is constant. Assuming the temperature remains constant as well, then the gas pressure is proportional to the number of moles:
so we can write
where
p1 = 730 mm Hg = 0.96 atm is the initial pressure
n1 = 0.650 mol is the initial number of moles
p2 = 1.15 atm is the final pressure
n2 is the final number of moles
Solving for n2,
Answer:
1,900 J
Explanation:
The number of moles of helium gas, n = 2 moles
The pressure of the helium gas, p = 1.0 × 10⁵ Pa
The initial temperature of the gas, T₁ = 2°C = 275.15 K
The final temperature of the gas, T₂ = 112°C = 385.15 K
The initial volume of the gas, V₁ = 45 liters
Cp = 20.8 J/(mol·K), Cv = 12.6 J/(mol·K)
The work done by the gas having constant pressure expansion is given as follows;
From the ideal gas law, we have;
Where;
R = The universal gas constant = 8.314 J/(mol×K)
Therefore, we get;
The work done, W = P ×ΔV = P × (V₂ - V₁)
∴ W = 1.0 × 10⁵ Pa × (64.0 L - 45.0 L) = 1,900 J
The work done by the gas as it expands, W = 1,900 J.