This question involves the concepts of equilibrium and Newton's third law of motion.
The support force will be "1 pound" for the empty bucket and the support force will be "6 pounds" after pouring water into it.
- According to the condition of equilibrium, the sum of forces acting on a stationary object must be zero. Hence, the support force of the table will be equal to the total mass of the bucket.
- According to Newton's Third Law of Motion every action force has an equal but opposite reaction force. Hence, the support force will be a reaction force to the weight of the bucket.
Therefore, the support force in each case will be equal to the total mass of the bucket:
Case 1 (empty bucket):
<u>support force = 1 pound</u>
<u></u>
Case 1 (water poured):
support force = 1 pound + 5 pound
<u>support force = 6 pound</u>
<u></u>
Learn more about equilibrium here:
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Answer:
The material must be durable (quality of the material requirement)
Explanation:
The design criteria set for the materials used for technological design are;
1) The materials should be affordable (less costly)
2) The materials should be last for a long duration (high durability)
3) The material should be readily available (easily sourced)
Therefore, given that the engineers initially had the criteria for the required plastic to be of high quality and to be readily available, and that the poly-carbonate they found is long lasting and not too costly, the criteria met that was set initially was the quality criteria of durability.
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Answer:
The final temperature of the two objects is the same.
Explanation:
The expression for the heat energy in terms of mass, specific heat and the change in the temperature is as follows:
Here, Q is the heat energy, m is the mass of the object, c is the specific heat and 
are the final temperature and initial temperature.
According to the given question, Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are added to each object.
............(1)
.............(2)
From (1) and (2),
Therefore, the final temperature of the two objects is the same.
