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3 years ago

Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .

Physics

1 answer:

Radda [10]3 years ago

7 0

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{160000}{270000} = \frac{16}{27} \\ = 0.592592...$

We have the final answer as

Hope this helps you

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5. When an object reaches terminal velocity its acceleration is

Vsevolod [243]

I think it is B. 4.9 m/s

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3 years ago

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Nuetrik [128]

Answer:

z = 93.2 m

Explanation:

We can appreciate that this expression is equivalent to the linear motion equation with constant acceleration

v² = v₀² + 2 a d

If we make a term-to-term comparison with the expression obtained, they are equivalent

u² = v² + 2 a z

From here we can clear the position

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z = (u² –v²) / 2 a

Let's calculate

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7 0

3 years ago

Help with this one please! Please give correct answers!

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4 years ago

If size of an image is 10 cm and the magnification produced by a mirror is +1, what will be the size of object?

olya-2409 [2.1K]

Answer:

h = 10 cm

Explanation:

The magnification produced by a mirror is given by :

$m=\dfrac{h'}{h}$

h' is the image size and h is the object size

We have, h = 10 cm, m = +1

So,

$m=\dfrac{h'}{h}\\\\h=\dfrac{10}{1}\\\\h=10\ cm$

So, the size off the object is same as that of the size of the image i.e. 10 cm.

3 0

3 years ago

A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of fri

Nikolay [14]

Answer:

the mass of the box is 51.98 kg.

Explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

$F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg$

Therefore, the mass of the box is 51.98 kg.

8 0

3 years ago