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3 years ago

Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .

Physics

1 answer:

Radda [10]3 years ago

7 0

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{160000}{270000} = \frac{16}{27} \\ = 0.592592...$

We have the final answer as

Hope this helps you

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How are physical traits inherited from one generation to the next?

Umnica [9.8K]

Http://www.nature.com/scitable/topicpage/inheritance-of-traits-by-offspring-follows-predictable-6524... this should answer all questions you have on this specific subject in science

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4 years ago

A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat

Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$1200=92t+\dfrac{1}{2}\times4t^2$

$2t^2+92-1200=0$

$t=10\ sec$

We need to calculate the velocity

Using equation of motion

$v=u+at$

Put the value into the formula

$v=92+4\times10$

$v=132\ m/s$

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

$h'=h+ut-\dfrac{1}{2}at^2$

Put the value into the formula

$0=1200+132t-\dfrac{1}{2}\times9.8t^2$

$4.9t^2-132t-1200=0$

$t=34\ sec$

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

$t'=34+10$

$t'=44\ sec$

Hence, The rocket above the ground is in 44 sec.

7 0

4 years ago

What is the density of iron if 5.0 cm3 has a mass of 39.5g

weqwewe [10]

Answer : $\rho = 7.9\ g/cm^3$

Explanation :

It is given that

Mass of iron, m = 39.5 g

Volume of iron, $V = 5\ cm^3$

So, density is :

density, $\rho =\dfrac{mass}{volume}$

$\rho =\dfrac{39.5g}{5cm^3}$

$\rho = 7.9\ g/cm^3$

7 0

4 years ago

A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.40 107 m/s and experiences an acceleration

noname [10]

Answer:

0.00956770833 T

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

m = Mass of proton = $1.67\times 10^{-27}\ kg$

a = Acceleration = $2.2\times 10^{13}\ m/s^2$

v = Velocity = $2.4\times 10^{7}\ m/s$

Magnetic field is given by

$B=\dfrac{ma}{qv}\\\Rightarrow B=\dfrac{1.67\times 10^{-27}\times 2.2\times 10^{13}}{1.6\times 10^{-19}\times 2.4\times 10^{7}}\\\Rightarrow B=0.00956770833\ T$

The magnetic field is 0.00956770833 T

4 0

3 years ago

A local fast food company sells a 16-oz soft drink. To determine if the soft drinks served contain < the advertised 16 oz, a

kakasveta [241]

Answer:

Hypothesis testing.

Explanation:

In the given problem it has been claimed that the mean of the population amount is less than 16 oz. for this claim, a test is conducted using the sample of size 20 and it was concluded that there is no evidence to say that mean amount is less than the claimed amount. i.e 16 oz

Hence, it is an example of the hypothesis testing.

6 0

3 years ago