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eduard
3 years ago
8

A simple pendulum 0.64m long has a period of 1.2seconds. Calculate the period of a similar pendulum 0.36m long in the same locat

ion.
Physics
1 answer:
weqwewe [10]3 years ago
8 0

The period of the second pendulum is 0.9 s

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity at the location of the pendulum

For the first pendulum, we have

L = 0.64 m

T = 1.2 s

Therefore we can find the value of g at that location:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{1.2})^2 (0.64)=17.5 m/s^2

Now we can find the period of the second pendulum at the same location, which is given by

T=2\pi \sqrt{\frac{L}{g}}

where we have

L = 0.36 m (length of the  second pendulum)

g=17.5 m/s^2

Substituting,

T=2\pi \sqrt{\frac{0.36}{17.5}}=0.9 s

#LearnwithBrainly

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In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str
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Answer:

Option D

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6 0
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F=13.965kg(m/s^2)
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3 0
4 years ago
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<h2>Thus the force of friction is 235 N</h2>

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Because the work done = Force x Distance

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3 0
3 years ago
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