Answer
given,
radius of earth,r = 1.5 x 10¹¹ m
Time,T = 365 days
= 365 x 24 x 3600 s
earth velocity,
v = 3 x 10⁴ m/s
centripetal acceleration of the earth
a = 6 x 10⁻³ m/s²
I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.
I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:
Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>
</span>
</span>
</span>
<span>
Distance at Perihelion
(</span></span><span>point in it's orbit that's closest to the sun):</span>
<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>
Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.
</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>
1/2 (50%) of that is 43.9845 Earth days
The average of the aphelion and perihelion distances is
1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU
This also happens to be 1/2 of the major axis of the elliptical orbit.
Answer:
2000years
Explanation:
We will either convert the distance to centimeters or speed to meters/second.
Converting distance to centimeters: 100 meters= 100*100centimeters =10000centimeters.
time=distance/speed
t=10000/5=2000 years
Answer: 4550 Joules
The formula for potential energy in gravitational field is as follows:
