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seraphim [82]
4 years ago
12

How do you calculate resistance with coulombs, time and J's?

Physics
1 answer:
Mars2501 [29]4 years ago
4 0
Hey user


The energy E in joules (J) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C):

E(J) = V(V) ×<span> Q</span>(C)

So

joule = volt × coulomb

or

J = V × C

Example

What is the energy in joules that is consumed in an electrical circuit with voltage supply of 15V and charge flow of 4 coulombs?

E = 15V × 4C = 60J

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Answer:

Voltage, V = 0.0524 volts

Explanation:

Thickness of the membrane, d=7.95\ nm=7.95\times 10^{-9}\ m

Electric field strength, E=6.6\ MV/m=6.6\times 10^6\ V/m

We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :

V=E\times d

V=6.6\times 10^6\ V/m\times 7.95\times 10^{-9}

V = 0.0524 volts

So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.

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