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3 years ago

When an object is thrown, the thrower pushes the object. This causes the object to move in a

Chemistry

2 answers:

kobusy [5.1K]3 years ago

6 0

Answer:

This causes the object to move in an oblique motion.

Explanation:

Oblique movement occurs when an object is thrown and begins its movement at a certain angle to the horizontal. In this type of throw, the object performs two simultaneous movements, while performing a vertical movement, rising and falling, also moving horizontally.

The analysis of the oblique throw must be made taking into account the movement executed vertically (y axis) and the horizontal movement (x axis). Regarding the movement in the y axis, the concern will be the determination of the maximum height reached by the body, because of the action of gravity in this axis the movement will be uniformly varied. X-axis motion analyzes will determine the horizontal range of the throw, ie the distance between the starting and finishing points. Horizontally, the movement will be rectilinear and uniform.

fgiga [73]3 years ago

3 0

This causes the object to move in a motion

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Each periods starts with a strong metal except the first period true or false

aleksandr82 [10.1K]

Answer: True

Explanation:

7 0

3 years ago

A freezer compartment is covered with a 2-mm-thick layer of frost at the time it malfunctions. If the compartment is in ambient

ruslelena [56]

Answer:

The time required to melt the frost is 3.25 hours.

Explanation:

The time required to melt the frost dependes on the latent heat of the frost and the amount of heat it is transfered by convection to the air .

The heat transferred per unit area can be expressed as:

$q=h_c*A*\Delta T\\\\q/A=h_c*\Delta T$

being hc the convective heat transfer coefficient (2 Wm^-2K^-1) and ΔT the difference of temperature (20-0=20 °C or K).

$q/A=h_c*\Delta T=2\frac{W}{m^2K}*20K=40\frac{W}{m^2}$

If we take 1 m^2 of ice, with 2 mm of thickness, we have this volume

$V=T*A = 0.002 m * 1 m^2=0.002m^3$

The mass of the frost can be estimated as

$M=\rho * V=700\frac{kg}{m^3}*0.002m^3= 1.4 kg$

Then, the amount of heat needed to melt this surface (1 m²) of frost is

$Q=L*M=334\frac{kJ}{kg}*1.4kg= 467.6kJ$

The time needed to melt the frost can be calculated as

$t=\frac{Q}{(q/A)}=\frac{467.6kJ/m2}{40W/m2} = 11.69\frac{kJ}{W}*\frac{1W*s}{1J}*\frac{1000J}{1kJ}= 11690s=3.25h$

7 0

3 years ago

What is the mass number of the isotope zinc – 65? a.30 b.65 c.35 d.95

aliina [53]

Atomic mass of zinc ( zn ) is 65 u

Answer B

3 0

4 years ago

A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from

sweet-ann [11.9K]

Answer:

$T_i~=163.1$ ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

Initial temperature of gold= Unknow

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the heat equation:

$Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT$

$Q_A_u=m_A_u*Cp_A_u*deltaT$

We can relate these equations if we take into account that all heat of gold is transfer to the water, so:

$m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT$

Now we can put the values into the equation:

$60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)$

Now we can solve for the initial temperature of gold, so:

$T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20$

$T_i~=163.1$ ºC

I hope it helps!

5 0

3 years ago

Neon doesn't take part in chemical reaction why give reason

ankoles [38]

Neon has filled its outer shells, therefore it is very stable and does not need to react with other elements and doesn’t form compounds.

5 0

3 years ago

Read 2 more answers