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natka813 [3]
4 years ago
14

In order to complete a lab, your teacher needs a 3.0 M solution of sulfuric acid, but only has a 12.0 M stock solution of sulfur

ic acid in the chemical store room. Calculate and describe the steps the teacher needs to take in order to make 100 mL of the 3.0 M solution of sulfuric acid.
Chemistry
1 answer:
Dimas [21]4 years ago
4 0

25 ml of the 12M solution will be diluted with water till volume made upto 100 ml to get a solution of 3M sulphuric acid.

Explanation:

Data given:

stock solution molarity (initial) = 12 M

Required molarity  (final)= 3M

Required volume (final)= 100ml

final volume = ?

So the formula used for dilution is:

Initial molarity X Initial volume = final molarity x final volume

initial volume = \frac{final molarity x final volume}{initial molarity}

putting the given values in the equation:

initial volume = \frac{3X100}{12}

                       = 25 ml

so, 25 ml of the original solution that is of 12 M will be diluted with water and volume made to 100ml will give a solution of 3M.

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Explanation:

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2 years ago
1. A 18 M solution of an acid that ionizes only slightly in solution would be termed___
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1x10^-14 = [OH-][H+]
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3 years ago
Does this difference in potential energy cause a release of energy or obsorption of energy from the atoms?
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8 0
3 years ago
What volume (in L) of carbon dioxide will be produced from the reaction of 37.4 L of oxygen?
Anna [14]

Answer:

21.4 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Volume of oxygen  = 37.4 L

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L

Now we will compare:

                              O₂             :              CO₂    

                              156.9         :              89.66

                                37.4         :             89.66/156.9×37.4 = 21.4 L

So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.

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3 years ago
How does the atomic radius of an element is related to its metallic character
Aneli [31]

Answer:

The large the atomic radius the more the metallic character of elements

Explanation:

The atomic radius is related to the metallic character in a way that the larger the atomic radius, the more metallic a body becomes.

Therefore, as we go down a group, metallic character increases.

  • Metallic character relies on the ability and willingness of an atom to share its valence electrons.
  • As the size of an atom becomes large, the more metallic it is and the more its metallic character.
  • In some other cases this character is known as electropositivity.
5 0
3 years ago
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