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4 years ago

If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?

Physics

1 answer:

Fittoniya [83]4 years ago

7 0

Answer:

The Kinetic Energy decreases. The Total Energy stays the same

Explanation:

The TE stays the same, so if PE increases then KE will decrease.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

emmasim [6.3K]

2+.5 + 2.5 all over 3

5/3

1.67k/h

=2.5

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3 years ago

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Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec

SOVA2 [1]

Answer:

$F_{net} = 6.879\times 10^{- 7}\ N$

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

$F = \frac{GMm}{\frac({d}{2}^{2})}$

$F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N$

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

$F_{net} = F + F'$

$F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N$

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3 years ago

Which nucleus completes the following equation?

algol [13]

1000000

Explanation

No equation for the following question was given

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4 years ago

A train is approaching a town at a constant speed of 12 m/s. The town is 1.0 km distant. After 30 seconds, the conductor applies

Yuliya22 [10]

To solve this problem we will apply the linear motion kinematic equations. To determine the position in which the braking starts we will start from the definition of distance as a function of speed and time, that is

$x = x_0 - vt$

Here,

$x_0$ = Initial position

v = Velocity

t = time

Replacing we have that

$x = 1000-12*30$

$x = 640m$

Now the acceleration is given by the function,

$v_f^2=v_0^2 +ax$

Here,

$v_f$ = Final velocity

$v_0$ = Initial velocity

a = Acceleration

x = Displacement

Replacing we have that

$0 = 12^2+2a(640)$

$a = -0.1125m/s^2$

Therefore the acceleration necessary to bring the train to rest is $-0.1125m/s^2$

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3 years ago

What do you know about earth?

solniwko [45]

Answer:Our home planet Earth is a rocky, terrestrial planet. It has a solid and active surface with mountains, valleys, canyons, plains and so much more. Earth is special because it is an ocean planet. Water covers 70% of Earth's surface.

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3 years ago

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