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laiz [17]
3 years ago
14

Please help

Physics
1 answer:
Andre45 [30]3 years ago
7 0

Answer:

your

answer is

12.004

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The force exerted by a magnetic field on a wire carrying current is:
F=ILB \sin \theta
where I is the current, L the length of the wire, B the magnetic field intensity, and \theta the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is 53 ^{\circ}, so we can re-arrange the formula and substitute the numbers to find B:
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