There are 2.1077x10^24 atoms of sulfur in 3.50 mols of sulfur.
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Answer:
- Satelites that collect information about the rover vehicle
- Distance space stations that store real-time data about the rover vehicle
- Doppler radar that records information about weather the rover is exposed to.
Explanation:
The first rover that landed on Mars was the Mars pathfinder (Sojourner) that landed on the 4th of July 1997.In total NASA has sent four rover to Mars.These are
- Sojourner
- Spirit
- Opportunity
- Curiosity
All five stars appear at the same place along the horizontal axis showing spectral type.
Because spectral type is related to surface temperature, all five stars must have the same surface temperature.
Now proceed to Part C to determine how these stars vary in luminosity.
<h3>What is a Star?</h3>
This refers to the heavenly body that is a natural luminous body that is visible in the sky, especially at night
Hence, we can see that based on the ranking of stars, the surface temperature of each star is taken into account, and based on their spectral type, the stars all have the same temperature.
Therefore, to show the difference between the stars, their luminous intensity needs to be analyzed,
Read more about stars here:
brainly.com/question/1320222
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Answer:
<em>The average acceleration is </em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the velocity of an object changes uniformly in time. If only the magnitudes are considered, then the equation that describes the change of speeds is:

Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The velocity (magnitude or speed) of a car increases from v0=2 m/s to vf=16 m/s in t=3.5 s. We can calculate the acceleration by solving for a:




The average acceleration is 