Explanation:
For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.
ΔU=Q−W
We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.
W=FΔx
W=3N×2m
W=6J
Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.
ΔU=Q−W
ΔU=10J−6J
ΔU=4J
Answer is 4J
i think this may help you very much
Answer:
Its a parallel connection
Explanation:
The bulbs aren't in one line but two different parts, which makes it a parallel connection instead of a series connection.
Answer:
12 (Magnesium- Mg)
Explanation:
Looking at the four numbers, we have:
Magnesium, Silicon, Sulfur, and Chlorine.
We can eliminate two of the answers immediately just by looking at the periodic table.
Sulfur and Chlorine are on the nonmetal side of the periodic table. So that's <em>definitely</em> not it. That leaves Magnesium and Silicon.
Silicon is a Metalloid. Magnesium is an Alkaline earth Metal.
Metaloids are elements that have a mix of both<em> metal</em> and<em> nonmetal </em>properties (luster, how it feels, etc.). Since it's a MIX and Magnesium is just straight METAL-
We can say Magnesium has the most metallic properties.
hope this helps!!
Vector trigonometry can be used for this problem. Since the horizontal component is 12 meters per second, this is technically the hypotenuse (actual initial velocity) multiplied to cosine of 40 degrees. Therefore, to find the hypotenuse, we must divide 12 by cosine 40degrees. cos(40)= 0.766, and 12/0.766 = approximately 15.664, therefore our answer is (3) 15.7 m/s
Answer:
a.
Explanation:
In a perfect system then energy can be changed from Kinetic to Gravitational Potential and vice versa without any losses. A common form of loss would be thermal energy, so b. is not the answer. c. is invalid as we want these 2 forms of energy to be transferred between, and d. is invalid as these statements c and a contradict each other.
