Answer:
6.9 g
Step-by-step explanation:
1. Use the Ideal Gas Law to find the <em>number of moles
</em>
pV = nRT Divide each side by RT
n = (pV)/(RT)
<em>Data:
</em>
p = 102 kPa
V = 6.0 L
R = 8.314 kPa·L·K⁻¹mol⁻¹
T = (37 + 273.15) K = 310.15 K
<em>Calculation:
</em>
n = (102 × 6.0)/(8.314 × 310.15)
n = 0.237 mol
2. Calculate the <em>mass of air
</em>
Mass of air = 0.237 mol × (29 g/1 mol)
Mass of air = 6.9 g
Answer:
The wavelength of these photons will become longer. The energy of each of these photons will become lower.
Explanation:
<h3>Wavelength</h3>
Light can be considered as electromagnetic waves. The wavelength of a wave is equal to the minimum distance between two troughs (lowest points) in this wave. On the other hand, the frequency of a wave is equal to the number of wavelengths that this wave travels in unit time.
Assume that the speed of light stays the same. The distance that this beam of light travels in unit time will be the same. However, with a lower frequency, there would be fewer wavelengths in that same distance. Therefore, the size of each wavelength will become longer.
If 
represent the speed of light and 
represents the frequency, then the wavelength would be:
.
<h3>Energy</h3>
The energy 
of each proton of a beam of light is proportional to the frequency of the light. Let 
denote Planck's Constant. The numerical relation between 
and 
would be:
.
Therefore, if the frequency of this light becomes smaller, the energy of each of its proton will also become proportionally lower.
Hello!
datos: Molarity = 
ps: The ionization constant of the sulfuric acid is strong and completely dissociates in water, so the pH will be:
![pH = - log\:[H_3O^+]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5C%3A%5BH_3O%5E%2B%5D%20)
![pH = - log\:[1*10^{-4}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5C%3A%5B1%2A10%5E%7B-4%7D%5D%20)
Note:. The pH <7, then we have an acidic solution.
I Hope this helps, greetings ... DexteR!
Answer:
The correct answer is "single replacement".
Explanation:
The activity series is a representation of a series of metals that are organized according to their order of reactivity. They start from the highest order of reactivity to the lowest order of reactivity.
The purpose of the series is to determine which products are formed in single-displacement reactions. The higher-order metals replace the lower order metals if there are two of them in the same solution. If metal is higher in the series it is more reactive than a metal that is below it in the activity series.
Have a nice day!
