Answer:
metal ball that moves at high speed
Explanation:
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!
2) Mass fraction of this is excessive data.
3) The solution is:
m(Ca)=1.2 g
m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)
m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
Answer:
sp
Explanation:
Hybridization is the combination of atomic orbitals to yield equivalent hybrid orbitals of appropriate energy which can participate in bonding.
In every compound there is a central atom. The central atom is usually the least electronegative atom in the molecule. In this case the least electronegative atom in the molecule is carbon.
The bond between carbon and oxygen in CO2 is intermittent between a pure double and a pure triple bond. Hence, carbon is sp hybridized.
volume of H₂O = 7.2 L
Explanation:
The combustion reaction of methane (CH₄):
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Now we calculate the number of moles of methane using the following formula:
number of moles = volume / 22.4 (L/mole)
number of moles of CH₄ = 3.6 / 22.4
number of moles of CH₄ = 0.16 moles
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mole of CH₄ produce 2 moles of H₂O
then 0.16 moles of CH₄ produce X moles of H₂O
X = (0.16 × 2) / 1 = 0.32 moles of H₂O
And now we can calculate the volume of water (H₂O) produced by the reaction:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4 (L/mole)
volume of H₂O = 0.32 × 22.4
volume of H₂O = 7.2 L
Learn more about:
combustion reaction
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Phosphorus can be prepared from calcium phosphate by the following reaction:
Phosphorite is a mineral that contains 
plus other non-phosphorus-containing compounds. What is the maximum amount of 
that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% by mass? Assume an excess of the other reactants.
Answer: Thus the maximum amount of that can be produced is 0.345 kg
Explanation:
Given mass of phosphorite = 2.3 kg
As given percentage of phosphorite is = 
According to stoichiometry:
2 moles of phosphorite gives = 1 mole of
Thus 5.56 moles of phosphorite give= 
of
Mass of 
Thus the maximum amount of that can be produced is 0.345 kg
