Given: A cubic tank holds 1,000.0 kg of water.
Mass of water in tank (m) = 1000.0 kg
Density of water (d) = 1000.0 kg /m³
Concept: Volume(V) = Mass / Density
Since the tank holds these water in it so the volume of water will be equal to the volume of the tank.
Hence, the volume of the tank = Mass of water / Density of water
or, = 1000.0 kg / 1000.0 kg m⁻³
or, = 1.0 m³
Since tank is cubical in shape. Let its side be 'x'
The volume of tank (x³) = 1.0 m³
or. side of tank (x) = 1.0 m
Hence, the dimensions of the tank will be 1.0 m.
Answer:
D. magnitude and direction
Explanation:
Picture #1:
GPE = (mass) x (gravity) x (height)
GPE = (2 kg) x (9.8 m/s²) x (40 m) = 784 joules
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (5 m/s)²
KE = (1 kg) (25 m²/s²) = 25 joules
Picture #2:
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (10 m/s)²
KE = (1 kg) (100 m²/s²) = 100 joules
Picture #3:
GPE = (mass) x (gravity) x (height)
GPE = (20 kg) x (9.8 m/s²) x (2 m) = 392 joules
KE = (1/2) (mass) (speed²)
KE = (1/2) (20 kg) (5 m/s)²
KE = (10 kg) (25 m²/s²) = 250 joules
Picture #4:
GPE = (mass) x (gravity) x (height)
98 joules = (1 kg) x (9.8 m/s²) x (height)
Height = (98 joules) / (1 kg x 9.8 m/s²)
Height = 10 meters
Picture #5:
GPE = (mass) x (gravity) x (height)
39,200 Joules = (mass) x (9.8 m/s²) x (20 m)
Mass = (39,200 joules) / (9.8 m/s² x 20 m)
Mass = 200 kg
No it all takes 9 or 10 months
