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Vitek1552 [10]
3 years ago
7

An aquarium has a volume of 2.75 cubic

Physics
1 answer:
Harlamova29_29 [7]3 years ago
3 0
The aquarium can hold 2750 liters because 1 cubic meter equals 1000 liters.
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The ball is moving at a constant speed of 0.5 m/s for 2.3 seconds how far does it go?
yarga [219]

Distance = (speed) x (time)

Distance = (0.5 m/s) x (2.3 s)

Distance = (0.5 x 2.3) m

Distance = 1.15 meters

7 0
4 years ago
The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on
Neporo4naja [7]

Answer:

162.8 K

Explanation:

initial current = io

final current, i = io/8

Let the potential difference is V.

coefficient of resistivity, α = 43 x 10^-3 /K

Let the resistance is R and the final resistance is Ro.

The resistance varies with temperature

R = Ro ( 1 + α ΔT)

V/i = V/io (1 + α ΔT )

8 = 1 + 43 x 10^-3 x ΔT

7 = 43 x 10^-3 x ΔT

ΔT = 162.8 K

Thus, the rise in temperature is 162.8 K.

5 0
3 years ago
If you want to know how energy will move between two objects, what do you need to know about the objects?
Inessa [10]
You need to know how much friction that object.
8 0
3 years ago
An electron moving at right angles to a 0.1 T magnetic field experiences an acceleration of 6 × 1015 m.s-2. What is the speed of
GaryK [48]

Explanation:

It is given that,

Magnetic field, B = 0.1 T

Acceleration, a=6\times 10^{15}\ m/s^2

Charge on electron, q=1.6\times 10^{-19}\ C    

Mass of electron, m=9.1\times 10^{-31}\ kg    

(a) The force acting on the electron when it is accelerated is, F = ma

The force acting on the electron when it is in magnetic field, F=qvB\ sin\theta

Here, \theta=90

So, ma=qvB

Where

v is the velocity of the electron

B is the magnetic field

v=\dfrac{ma}{qB}

v=\dfrac{9.1\times 10^{-31}\ kg\times 6\times 10^{15}\ m/s^2}{1.6\times 10^{-19}\ C\times 0.1\ T}

v = 341250  m/s

or

v=3.41\times 10^5\ m/s

So, the speed of the electron is 3.41\times 10^5\ m/s

(b) In 1 ns, the speed of the electron remains the same as the force is perpendicular to the cross product of velocity and the magnetic field.

7 0
3 years ago
How much force is needed to lift a 25-kg mass at a constant verlocity?
Troyanec [42]

-- In order to achieve constant verlocity, the net force on the mass must be zero.  So if there ARE any forces acting on it, they must be balanced.

-- There is already a force on the mass that can't be eliminated . . . the force of gravity.

-- That force due to gravity is (mass x gravity) = (25 kg)(9.8 m/s²) = <em><u>245N</u></em> in the <u><em>downward</em></u> direction.

-- In order to 'balance' the forces and make them add up to zero, we have to provide another force of <em>245N</em>, all in the <em>upward</em> direction.

-- Then the forces on the object will be balanced, the NET force on it will be zero, and whichever way you start it moving, it will continue to move at a cornstant verlocity.

5 0
3 years ago
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