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alexgriva [62]
3 years ago
7

Which is an equation of the line perpendicular to y = -3/4x + 1 and passes through (3, 4)?

Mathematics
1 answer:
topjm [15]3 years ago
5 0

Answer:

Step-by-step explanation:

perp. 4/3

y - 4 = 4/3(x - 3)

y - 4 = 4/3x - 4

y = 4/3x

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The difference of twelve times a number and nine times a number
inna [77]

Since the problem states "a number" and again "a number", I assume it;'s the same number. Let the number be x.

12x - 9x = 3x

The difference of twelve times a number and nine times a number is three times the number.

6 0
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Read 2 more answers
Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected.
Leno4ka [110]

As the problem indicates, degrees of freedom are the number of values ​​that can be independently selected before it is necessary to choose specific values ​​to arrive at the desired result.

The average, on the other hand, results from the sum of a list of values ​​divided by the amount of values ​​in the summed list.

Assume that the mean sought is x and consider that the list is composed of a single element a, in that case no random number can be selected, since the mean x must correspond to that number.

If the list were composed of two elements a and b, one of the two values ​​could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in 2x, this given that the formula of the average \sum\limits_{i=1}^n \frac{ x_{i}}{n}.

With three values ​​a, b and c, it is possible to select two freely, since the thirteen must be the one that balances the sum of a+b, that is (a + b) + c = 3x.

Thus, in general, with n values, it is possible to select n-1 values ​​freely whose sum must be balanced by the last value so that the whole sum is nx.

Answer

In a list of \bf{n} values ​​you can assign \bf{n-1} values ​​freely, that is, you have n-1<em>degrees of freedom.</em>

6 0
3 years ago
Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.
Kipish [7]
Hello!!

Equation forms:

y =  \frac{x^2}{4} +  \frac{x}{2} +  \frac{13}{4}

Therefore, x^2 - 2x + 4y - 13 = 0

And, this is how your graph would look

Good luck :)

8 0
2 years ago
Assume all variables represent non negative numbers . Help please!!
Dafna1 [17]

Answer:

A). 2p^{8}

B). 3m^{7}

Step-by-step explanation:

A). \sqrt{4p^{16}}

    To get the square root of the given expression we will convert it into the square form.

4p^{16}=(2)^2(p^{8})^2 [Since 2×2 = 4 and p^{8}\times p^{8}=p^{16}]

Therefore, \sqrt{4p^{16}}=\sqrt{2^{2}\times (p^{8})^2 }

                             =2p^{8}

B). \sqrt{9m^{44}}

    Since, 9m^{14}=(3)^2\times (m^7)^2

    Therefore,  \sqrt{9m^{44}}=\sqrt{(3)^2\times (m^7)^2} [Since 3² = 9 and (m⁷)² = m¹⁴]

                                   =3m^{7}

7 0
3 years ago
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