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weqwewe [10]
3 years ago
5

What makes a force a vector quantity

Physics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

A vector quantity is a quantity that has both magnitude and direction.

Explanation:

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Are dimensionless quantities always unitless​
timofeeve [1]

<em>Important thing is that all unitless quantity is dimensionless quantity. .</em><em>A</em><em> dimensionless physical quantity may have an unit</em>

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3 years ago
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Anyone know the answer to number 4…..please help me ASAP!
Damm [24]

Answer:

All planets have an elliptical orbit

all planets have roughly the same SHAPE of orbit

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A spinning turbine at an electrical plant produces energy that flows through wires to your house. The energy in the wires can be
Anna007 [38]

The spinning turbine converts mechanical energy into electrical energy that is converted into light energy used to light up the house.

<h3>What is law conservation of energy?</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

The spinning turbine works on the principle of mechanical energy.

Thus, the spinning turbine converts mechanical energy into electrical energy that is converted into light energy used to light up the house.

Learn more about mechanical energy here: brainly.com/question/24443465

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6 0
2 years ago
To test the hypothesis that the population mean mu=3. 6, a sample size n=14 yields a sample mean 4. 007 and sample standard devi
PolarNik [594]

The P value for the given data set is 25127. For finding P value, we have to must find the Z value.

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

The Z value is calculated as;

Z = \dfrac{X - \mu}{\sigma})

Z = (X - μ) / σ

Z = (4.007 - 3.6) / 0.607

Z = 0.67051

The P value for the given data set is 25127.

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5 0
2 years ago
At noon on a clear day, sunlight reaches the earth\'s surface at Madison, Wisconsin, with an average intensity of approximately
Dmitrij [34]

Intensity of sunlight at given position is defined as power received per unit area

so here we can say

I = 2 kJ/s*m^2

area  on which photons are received is given as

A = 4.80 cm^2 = 4.80 * 10^-4 m^2

now we can find the power received due to sunlight

P = I*A

P = 2* 10^3 * 4.80 * 10^-4

P = 0.96 Watt

now we can say this power is due to photons that strikes on surface of earth

so here we can say

P = N\frac{hc}{\lambda}

given here that

\lambda = 510 nm

0.96 = N\frac{6.6 * 10^{-34}* 3 * 10^8}{510*10^{-9}}

0.96 = N * 3.88 * 10^{-19}

N = \frac{0.96}{3.88*10^{-19}}

N = 2.47 * 10^{18}

so it will strike 2.47 * 10^18 photons on given area per second

3 0
3 years ago
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