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Elena-2011 [213]
3 years ago
6

To verify that this expression for (vf)α has the correct units of velocity, you need to perform some unit analysis. begin by fin

ding the equivalent of a volt in terms of basic si units. what is a volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)?
Physics
1 answer:
Ket [755]3 years ago
7 0
<h2>Answer</h2>

1 V = 1 kg m2 s−² C

1 V = 1 kg m2 s−³ A−1

(one kilogram meter squared per second cubed per ampere)

<h2>Explanation</h2>

<em>The work required to move an electric charge of one coulomb through an electrical potential difference of one volt,</em>

<h2> Volts = Joules / Coulombs</h2><h2 />

    Joules = Newton x metre

     Volts = Nm / coulombs

    Newton = kg x metre / second ²

    Volts = kg x metre / second ² coulombs

Volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)

<h3>For further:</h3>

Coulomb = Amp * second

Volts = kg x metre / second ³ Amp

<h2 />

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Identify which one is chemical change, chemical property,physical change and physical property
Ulleksa [173]

Answer:

Heat conductivity: Physical property

Silver tarnishing: chemical change

Sublimation: physical change

Magnetizing steel: physical property

Length of a metal object: physical property

Shortening melting: physical property

exploding dynamite: chemical change

combustible: chemical property

water freezing: physical change

Acid resistance: chemical property

brittleness: physical property

milk souring: chemical change

baking bread: chemical change

Explanation:

First you need to understand the differences between physical and chemical change; physical and chemical property.

<u>Physical properties vs chemical properties:</u>

Physical properties are properties that you can observe without changing the substance's composition. This means you can measure these properties without changing them chemically.

Chemical properties, on the other hand, are properties are not as direct. These properties are generally determined by the way the react with other substances changing their composition.

<u>Physical changes vs chemical changes:</u>

A substance that undergoes physical change does not change in chemical composition. They may look physically different in terms of size and shape, but overall, their chemical composition remains constant. The best example would be water. Water can change phases, from solid to liquid when they melt. Essentially, they look like different substances, but the change is only physical and not chemical.

Chemical change, is different by the fact that they change in chemical composition. Bonds are broken and/or made through the reaction, which changes them not only physically but chemically as well. Some of the most indicative signs of a chemical change occurring are: change in color, odor, production of gas, production of light/heat.

4 0
3 years ago
How do you solve 0.004 dm + 0.12508 dm?
Effectus [21]
0.004 of something added to 0.12508 of the same thing
adds up to 0.12908 of it.  

The thing could be a glass of water, a sheet of paper,
a pound of ground beef, a gallon of gas, or a snowball.  
In this problem, it just happens to be a dm. 
7 0
3 years ago
YOU READING THIS PLEASE GIVE ME A EASY 7TH GRADE TOPIC NO VOLCANIOS
Kipish [7]
Photothysenis. or fossils they are very easy
6 0
3 years ago
Read 2 more answers
If a moving car speeds up until it is going twice as fast, how much kinetic energy doe s it have compared with its initial kinet
dezoksy [38]
The kinetic energy of an object of mass m and velocity v is given by
K= \frac{1}{2} mv^2

Let's call v_i the initial speed of the car, so that its initial kinetic energy is
K_i =  \frac{1}{2} mv_i^2
where m is the mass of the car. 

The problem says that the car speeds up until its velocity is twice the original one, so 
v_f = 2 v_i
and by using the new velocity we can calculate the final kinetic energy of the car
K_f =  \frac{1}{2} mv_f^2 =  \frac{1}{2}m (2 v_i)^2 = 4 ( \frac{1}{2} mv_i^2)=4 K_i
so, if the velocity of the car is doubled, the new kinetic energy is 4 times the initial kinetic energy.
6 0
3 years ago
11–8 Consider a heavy car submerged in water in a lake with a flat bottom. The driver’s side door of the car is 1.1 m high and 0
Greeley [361]

Answer:

Explanation:

position of centre of mass of door from surface of water

= 10 + 1.1 / 2

= 10.55 m

Pressure on centre of mass

atmospheric pressure + pressure due to water column

10 ⁵ + hdg

= 10⁵ + 10.55 x 1000 x 9.8

= 2.0339 x 10⁵ Pa

the net force acting on the door (normal to its surface)

= pressure at the centre x area of the door

= .9 x 1.1 x 2.0339 x 10⁵

= 2.01356 x 10⁵ N

pressure centre will be at 10.55 m below the surface.

When the car is filled with air or  it is filled with water , in both the cases pressure centre will lie at the centre of the car .

7 0
3 years ago
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