The answer is D=M/V hope it helps!!
Answer:
Displacement after 5 seconds is 155/2 meters
Explanation:
Let X (t) represent the equation of the position, then you have to d2x / dt2 = 5.
Applying the fundamental theorem of the calculation dx/dt = 5t + vo. The speed equation is V (t) = 5t + vo. Since the initial velocity is 30m/s, V (0) = 5 (0) + vo = 30. Therefore, V (t) = dx/dt = 5t + 30. Applying again the fundamental theorem of the calculation X (t) = 5t^2 / 2 + 30t + xo.
Displacement in 5 seconds is given by X (5) - X (0).
X (5) - X (0) = 5 (5)^2/2 +3 (5) + Xo - 5 (0)^2/2 -3 (0) -Xo = 155/2
Displacement after 5 seconds is 155/2 meters
I think it will be the one with the more inertia
im not sure but hope this somewhat helped
Answer:
Weight = 966 Newton.
Explanation:
Given the following data;
Length = 1.2 m
Width = 2.3 m
Pressure = 350 Pa
To find the weight of the tank;
We know that weight is the force of gravity acting on an object multiplied by its mass.
Weight = mg = force
Hence, we would determine the force using the parameters that were given.
But we would first determine the area of the rectangular tank.
Area of rectangle, A = length * width
A = 1.2 * 2.3
A = 2.76 m²
Mathematically, pressure is given by the formula;
Pressure = force/area
Force = pressure * area
Substituting into the formula, we have;
Force = 2.76 * 350
Force = 966 Newton
Therefore, the weight of the tank is 966 Newton.
Here it is. It was too much to type on a phone....
