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Aleks [24]
3 years ago
6

Waht is the first six nonzero multiples

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0
5*1=5
5*3=15
5*5=25
5*7=35
5*9=45
5*11=55
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​ AD​ , BD , and CD are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m.
suter [353]

The answer is 16

And also , can people please stop posting did you get the answer yet, just so you could get the  points.  They only take two answers, and that's a waste of somebody who could've answered or helped.

8 0
3 years ago
Read 2 more answers
a famer has 120 feet of fencing with whcih to enclose two adjacent rectangular pens as shown. what dimeensions should be used th
Nat2105 [25]

The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.

Let the area be y .

Area = (base) × (height)

Base = 2x

Height = h

Let the area of the rectangular pens be y .

∴ y = 2xh

Perimeter of all the fencing = 4x+3h

∴ 4x+3h = 120

now we solve for h

3h = 120-4x

h = 40 - 4/3 x

Now we will substitute this value in the above first equation:

y = 2xh

or, y = 2x (40 - 4/3 x)

or, y = 80x - 8/3 x²

Now for the maximum area we have to find the first order differentiation of y

now,

dy /dx = 80 - 16/3 x

At dy/dx = 0 we get the value of x for which y is maximum.

80 - 16/3 x = 0

or, - 16/3 x = -80

or, x = 15 feet

Hence height =  40 - 4/3 x = 40 - 20 = 20feet

Maximum area = 2xh = 2×15×40 = 1200 square feet

The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.

Disclaimer : The missing figure for the question is attached below.

To learn more about area visit:

brainly.com/question/27531272

#SPJ4

6 0
2 years ago
A Fulcrum of a Pyramid is 6cm Square at the
Len [333]

Answer:

288 cubic cm

Step-by-step explanation:

Volume of the pyramid = 1/3 * base area * height

Base area = 12 * 12

Base area - 144 sq. cm

Height = 6cm

Volume of the pyramid = 144 * 6/3

Volume of the pyramid = 144 * 2

Volume of the pyramid  = 288 cubic cm

4 0
3 years ago
Determine the fraction of total interest owed using the rule of 78. After the six month of a 12 month loan, the numerator is: {(
Dima020 [189]

Answer:

The fraction of total interest owed is  \frac{57}{78}

The value of it to the nearest tenth is 73.1%

Step-by-step explanation:

Let us solve it using the rule of 78

∵ The loan = 12 month

∵ The numerator is after 6 month

- Substitute n by 1 in each bracket

∴ The numerator = {(1 + 11) + (1 + 10) + (1 + 9) + (1 + 8) + (1 + 7) + (1 + 6)}

∴ The numerator = {12 + 11 + 10 + 9 + 8 + 7}

∴ The numerator = {57}

∴ The numerator of the fraction is 57

∵ The denominator = {(n) + (n + 1) + (n + 2) + .......... + (n + 11)}

- substitute n by 1 in each bracket

∴ The denominator = {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12}

∴ The denominator = {78}

∴ The denominator of the fraction is 78

The fraction of total interest owed is  \frac{57}{78}

Now find the value of the fraction

∵ The fraction = \frac{57}{78}

∴ Its value = 0.7307692308 × 100%

∴ Its value = 73.07692308%

- Round it to the nearest tenth

∴ Its value = 73.1%

The value of it to the nearest tenth is 73.1%

5 0
3 years ago
Rewrite the fraction as a decimal -33/25
sergiy2304 [10]
To rewrite something as a decimal, simply divide the numerator and denominator.
-33 / 25 = -1.32
So -33/25 = -1.32
3 0
3 years ago
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