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777dan777 [17]
3 years ago
8

Need help plzz

Chemistry
1 answer:
Sveta_85 [38]3 years ago
5 0

_____ are types of active transport.

(A)Diffusion and osmosis

<u>(B)Engulfing and transport proteins </u>

(C)Osmosis and engulfing

(D)Transport proteins and diffusion

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Imagine a chemist is in the lab and trying to make some chemical reactions happen. In one reaction she reacts chemicals in an ex
VikaD [51]

Imagine a chemist is in the lab and trying to make some chemical reactions happen. In one reaction she reacts chemicals in an exothermic reaction and there is an increase in entropy. A second chemical reaction she is trying to run is endothermic and there is a decrease in entropy. Which of the two reactions is more likely to occur and why?

4 0
3 years ago
A gas at 750 mmhg and with a volume of 2. 00 l is allowed to change its volume at constant temperature until the pressure is 600
Gemiola [76]

Answer:

The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.

Explanation:

Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;

P ∝ V

P V = K

P1 V1 = P2 V2

Parameters :

P1 = Initial pressure of the gas = 750 mmHg

V1 = Initial pressure of the gas = 2. 00 Liters

P2 = Final pressure of the gas = 600 mmHg

V2 = Fimal volume of the gas = ? Liters

Calculations :

V2 = P1 V1 ÷ P2

V2= 750 × 2. 00 ÷ 600

V2 = 1500 ÷ 600

V2 = 2.5 Liters.

Therefore, the new volume of the gas is 2. 5 Liters.

8 0
2 years ago
Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.
dem82 [27]
2C4H10 + 13O2 = 8CO2 + 10H2O

1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10

2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O

3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
8 0
3 years ago
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
musickatia [10]

Answer:

T_2=335.42K=62.27^oC

Explanation:

Hello,

In this case, by using the general gas law, that allows us to understand the pressure-volume-temperature relationship as shown below:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, solving for the temperature at the end (considering absolute units of Kelvin), we obtain:

T_2=\frac{P_2V_2T_1}{P_1V_1}=\frac{1.8L*0.75atm*(25+273.15)K}{1.2L*1.0atm} \\\\T_2=335.42K=62.27^oC

Best regards.

4 0
3 years ago
Read 2 more answers
Chemistryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
mrs_skeptik [129]
Water is your answer!!!!!!!!!
5 0
3 years ago
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