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liubo4ka [24]
3 years ago
9

Based on the equations below, which metal is the most active? pb(no3)2 (aq) + ni (s) â ni(no3)2 (aq) + pb (s) pb(no3)2 (aq) + ag

(s) â no reaction cu(no3)2 (aq) + ni (s) â ni(no3)2 (aq) + cu (s)
Chemistry
1 answer:
erastova [34]3 years ago
3 0

Answer is: nickel (Ni) is the most active metal.

Chemical reaction 1: Pb(NO₃)₂(aq) + Ni(s) → Ni(NO₃)₂(aq) + Pb(s).

Chemical reaction 2: Pb(NO₃)₂(aq) + Ag(s) → no reaction.

Chemical reaction 3: Cu(NO₃)₂(aq)) + Ni(s) → Ni(NO₃)₂(aq) + Cu(s).

From chemical reactions 1 and 3, we can conclude that nickel is more reactive than lead (Pb) and copper (Cu), because lead is more reactive than silver (Ag), chemical reaction 2, nickel is also more reactive than silver.

In chemical reaction 2, no reaction occurs because silver is less reactive than lead. Lead is higher in activity series of metals and can not be reduced.

Nickel is higher in activity series of metals than lead, copper and silver.

The activity series is a series of metals from highest to lowest reactivity. Metal higher in the reactivity series will displace another.

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Can someone help me with number 1 and 2 plz!
GalinKa [24]

Answer:

1) 0 N

2) 8 N

Explanation:

The net force is the sum of all of the forces acting on the object.

For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left.  If we define the right to be positive and the left to be negative, then the net force equals:

Fnet = 5N - 5N = 0 N

Therefore, the net force in question 1 is 0 N.

For question 2, the process is very similar.  We want to find the sum of the forces acting on the object.  In this case, there are forces of 3 N and 5 N acting to the right.

Fnet = 3 N + 5 N = 8 N

Therefore, the net force in question 2 is 8 N.

Hope this helps!

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