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kakasveta [241]
3 years ago
8

Add more drink mix until you notice a color change. Have you increased or decreased the concentration? (Higher number means a hi

gher concentration).
Chemistry
1 answer:
valina [46]3 years ago
3 0

Answer:

Increased the concentration

Explanation:

Complete Question

Open the simulation by pushing the play button.  Begin by dragging the concentration tester overto the liquid and add drink mix until the concentration reaches approximately 2.oo mol/L.  This means there are 2.00 moles of the drink mix in 1 Liter of the solution. Add more drink mix until you notice a color change. Have you increased or decreased the concentration? (Higher number means a higher concentration).

Solution

Drink mix is basically the solute which is added to solvent i.e water.

The higher is the amount of drink mix in the solvent, the higher is the concentration of the solute and hence darker is the color of the drink.

Hence, in the case the concentration of the drink has been increased.

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How many moles are in 5.96g of MgCO,?
nikdorinn [45]

Answer:

201.1046

hope that helped :)

6 0
3 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
How many grams of He are necessary to fill a balloon having a volume of 4.50 × 10^{3} mL to a pressure of 1.14 × 10^{3} torr at
lana [24]

The mass in grams of He are necessary to fill a balloon having a volume of 4.50×10³ mL to a pressure of 1.14×10³ torr at 25.0ºC is 1.104 grams.

<h3>How do we calculate the grams from moles?</h3>

Mass (W) in grams from moles (n) will be calculated by using the below equation:
n = W/M, where

M = molar mass

Moles of helium gas will be calculated by using the ideal gas equation:

PV = nRT, where

R = universal gas constant = 62.363 L.torr / K.mol

P = pressure of gas = 1.14×10³ torr

V = volume of gas = 4.50×10³ mL = 4.50 L

n = moles of gas = ?

T = temperature = 25.0ºC = 298 K

On putting these values on the ideal gas equation, we get

n = (1140)(4.5) / (62.363)(298) = 5130 / 18584

n = 0.276 moles

Now we convert this moles into mass by using the first equation as:

W = (0.276mol)(4g/mol) = 1.104 g

Hence required mass of helium gas is 1.104 grams.

To know more about ideal gas equation, visit the below link:

brainly.com/question/12873752

#SPJ1

5 0
2 years ago
The length of a copper wire is 1.6 centimeters (cm). What is the length of this wire in meters (m)? 1.6 mc031-1.jpg 10–3 m 1.6 m
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I believe the answer is  0.016. if i am wrong please tell me if it's wrong. the second option 
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