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2 years ago

In the reaction _Al 3O2→2Al2O3, what coefficient should be placed in front of the Al to balance the reaction? 1 2 3 4.

Chemistry

1 answer:

luda_lava [24]2 years ago

4 0

Answer:

D.) 4

Explanation:

Al + 3 O₂ --> 2 Al₂O₃

In the equation, there are:

Reactants: 1 Al and 6 O

Products: 4 Al and 6 O

To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.

The new equation would look this this:

4 Al + 3 O₂ --> 2 Al₂O₃

There are now:

Reactants: 4 Al and 6 O

Products: 4 Al and 6 O

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In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb

gtnhenbr [62]

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

In which pair do both compounds exhibit predominantly ionic bonding?

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

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2 years ago

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq

Inga [223]

Answer:

$M_{acid}=0.0444M$

Explanation:

Hello,

In this case, for the given reaction:

$H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4$

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

$2*n_{acid}=n_{base}$

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

$2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M$

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5 0

3 years ago

Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K

Elenna [48]

Answer:

The pressure of CO2 = 0.48 atm

Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)

Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

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3 years ago

Calculate the half-life of different radioactive sources.

otez555 [7]

The rate at which a radioactive isotope decays is measured in half-life. The termhalf-life is defined as the time it takes for one-half of the atoms of a radioactive material to disintegrate. Half-lives for various radioisotopes can range from a few microseconds to billions of years.
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7 0

3 years ago

"Which statement is true about the removal of a terminal phosphate" from ATP? Choose one: A. The reaction is associated with a p

Mamont248 [21]

Answer:

C. The reaction is energetically favorable.

Explanation:

The reaction which shows the removal of the terminal phosphate from the ATP is shown below:

$ATP+H_2O\rightarrow ADP+P_i+\ energy$

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Hence, Option A is not correct.

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Hence, Option B is not correct.

The Gibbs' free energy change is negative which means that the reaction is energetically favorable.

Option C is correct.

6 0

3 years ago